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Manipulation of algebraic fractions

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Determine the partial fraction breakdown of the following expression:

\n

     \\(I(s)=\\frac{\\var{R}s+\\var{T}}{(s+\\var{a})(s+\\var{b})(s+\\var{c})}\\)

", "advice": "

\\(\\frac{\\var{R}s+\\var{T}}{(s+\\var{a})(s+\\var{b})(s+\\var{c})}=\\frac{A}{s+\\var{a}}+\\frac{B}{s+\\var{b}}+\\frac{C}{s+\\var{c}}\\)

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Mutiply across by the denominator \\((s+\\var{a})(s+\\var{b})(s+\\var{c})\\) to get

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\\(\\var{R}s+\\var{T}=A(s+\\var{b})(s+\\var{c})+B(s+\\var{a})(s+\\var{c})+C(s+\\var{a})(s+\\var{b})\\)

\n

let s = \\(-\\var{a}\\)

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\\(\\simplify{{R}*{-{a}}+{T}}=\\simplify{(-{a}+{b})*(-{a}+{c})}A\\)

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\\(A=\\simplify{{{R}*{-{a}}+{T}}/((-{a}+{b})*(-{a}+{c}))}\\)

\n

let s = \\(-\\var{b}\\)

\n

\\(\\simplify{{R}*{-{b}}+{T}}=\\simplify{(-{b}+{a})*(-{b}+{c})}B\\)

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\\(B=\\simplify{{{R}*{-{b}}+{T}}/((-{b}+{a})*(-{b}+{c}))}\\)

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let s = \\(-\\var{c}\\)

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\\(\\simplify{{R}*{-{c}}+{T}}=\\simplify{(-{c}+{a})*(-{c}+{b})}C\\)

\n

\\(C=\\simplify{{{R}*{-{c}}+{T}}/((-{c}+{b})*(-{c}+{a}))}\\)

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Express your answer as a sum of three fractions:

\n

               \\(I(s) =\\) [[0]]

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