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Solve a logarithmic equation

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Encuentre el valor de \\(x\\) que satisface la siguiente ecuación:

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\\(\\var{a}\\log(\\var{b}x+\\var{c})=\\var{d}\\)

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\\(\\var{a}\\log(\\var{b}x+\\var{c})=\\var{d}\\)

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Dividiendo a ambos lados por \\(\\var{a}\\)

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\\(\\log(\\var{b}x+\\var{c})=\\simplify{{d}/{a}}\\)

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\\(\\var{b}x+\\var{c}=10^{\\simplify{{d}/{a}}}\\)

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\\(\\var{b}x+\\var{c}=\\simplify{10^{{d}/{a}}}\\)

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\\(\\var{b}x=\\simplify{10^{{d}/{a}}}-\\var{c}\\)

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\\(\\var{b}x=\\simplify{10^{{d}/{a}}-{c}}\\)

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\\(x=\\simplify{(10^{{d}/{a}}-{c})/{b}}\\)

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Ingresa tu respuesta con 3 decimales:

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\\(x = \\) [[0]]

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