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La siguiente ecuación puede ser convertida a una ecuación cuadrática. Encuentre los valores de $x$ que satisfacen esta ecuación.

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\\(\\var{a1}x+\\dfrac{\\simplify{{a1}*{b1}*{c1}}}{x}=\\simplify{{a1}*({b1}+{c1})}\\)

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Solving quadratic equations using a formula

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\\(\\var{a1}x+\\dfrac{\\simplify{{a1}*{b1}*{c1}}}{x}=\\simplify{{a1}*({b1}+{c1})}\\)

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Multiplicando cada término de la ecuación por \\(x\\) obtenemos

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\\(\\var{a1}x^2+\\simplify{{a1}*{b1}*{c1}}=\\simplify{{a1}*({b1}+{c1})}x\\)

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Llevamos todos los términos al lado izquierdo y los ordenamos de acuerdo a las potencias de \\(x\\) para obtener

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\\(\\var{a1}x^2-\\simplify{{a1}*({b1}+{c1})}x+\\simplify{{a1}*{b1}*{c1}}=0\\)

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La fórmula para resolver una ecuación cuadrática de la forma \\(ax^2+bx+c=0\\)  está dada por

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\\(x=\\dfrac{-b\\pm \\sqrt{b^2-4ac}}{2a}\\)

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En este ejemplo,  \\(a=\\var{a1},\\,\\,\\,b=\\simplify{+-{a1}*({b1}+{c1})}\\)  y \\(c=\\simplify{{a1}*{b1}*{c1}}\\)

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\\(x=\\dfrac{\\var{b}\\pm \\sqrt{(-\\var{b})^2-4*\\var{a1}*\\var{c}}}{2*\\var{a1}}\\)

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\\(x=\\dfrac{\\var{b}\\pm \\sqrt{\\simplify{{b}^2-4*{a1}*{c}}}}{\\simplify{2*{a1}}}\\)

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\\(x=\\simplify{{b}+({b}^2-4*{a1}*{c})^0.5}/\\simplify{2*{a1}}=\\simplify{({b}+({b}^2-4*{a1}*{c})^0.5)/(2*{a1})}\\)        o bien        \\(x=\\simplify{{b}-({b}^2-4*{a1}*{c})^0.5}/\\simplify{2*{a1}}=\\simplify{({b}-({b}^2-4*{a1}*{c})^0.5)/(2*{a1})}\\)

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Ingrese el mayor de los valores que satisfacen la ecuación. 

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\\(x = \\) [[0]]

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Ingrese el menor de los valores que satisfacen la ecuación. 

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\\(x = \\) [[1]]

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