// Numbas version: finer_feedback_settings {"name": "Limits: L'Hospital's rule: Indeterminate form infinity/infinity", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"parts": [{"prompt": "
As {choice2[0]}, {choice2[2]} approaches [[0]]
\nNote: infinity is simply entered by typing infinity
\n", "variableReplacementStrategy": "originalfirst", "gaps": [{"minValue": "choice2[-1]", "mustBeReduced": false, "mustBeReducedPC": 0, "marks": 1, "showCorrectAnswer": true, "scripts": {}, "showFeedbackIcon": true, "correctAnswerFraction": false, "notationStyles": ["plain", "en", "si-en"], "maxValue": "choice2[-1]", "correctAnswerStyle": "plain", "variableReplacementStrategy": "originalfirst", "type": "numberentry", "allowFractions": false, "variableReplacements": []}], "type": "gapfill", "showCorrectAnswer": true, "scripts": {}, "showFeedbackIcon": true, "marks": 0, "variableReplacements": []}], "preamble": {"css": "", "js": ""}, "statement": "This question is about limits of indeterminate forms.
", "variablesTest": {"maxRuns": 100, "condition": ""}, "functions": {}, "advice": "As {choice2[0]}, it appears {choice2[2]} approaches {choice2[1]}, but it isn't clear what this means. This is known as an indeterminate form of type {choice2[1]}. L'Hospital's rule says that if we have such an indeterminate form we can differentiate the numerator and denominator separately and take the limit of the quotient. That is, if $f$ and $g$ are differentiable on an open interval containing $a$, $g'(x)\\ne 0$ on that interval (except possibly at $x=a$), $\\lim_{x\\rightarrow a}f(x)=\\infty$, $\\lim_{x\\rightarrow a}g(x)=\\infty$ and $\\lim_{x\\rightarrow a}\\frac{f'(x)}{g'(x)}$ exists (or equals $\\pm\\infty)$ then:
\n\\[\\lim_{x\\rightarrow a} \\frac{f(x)}{g(x)}=\\lim_{x\\rightarrow a}\\frac{f'(x)}{g'(x)}.\\]
\n(If this is still an indeterminate form we can (of course) repeat the procedure)
\n\nSo by applying L'Hospital's rule we now need to determine what {choice2[3]} approaches as {choice2[0]}. But this is again an indeterminate form so we repeatedly apply L'Hospital's rule until it is not an indeterminate form and we arrive at needing to determine what {choice2[4]} approaches as {choice2[0]}. Now that this is no longer an indeterminate form, it should be clear that the limit is $\\var{choice2[-1]}$.
\n", "metadata": {"description": "Just what the title says, I guess.
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", "name": "log_root", "templateType": "anything", "group": "Ungrouped variables"}, "pL": {"definition": "shuffle(1..12)[0..5]", "description": "", "name": "pL", "templateType": "anything", "group": "Ungrouped variables"}}, "type": "question", "contributors": [{"name": "Ben Brawn", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/605/"}]}]}], "contributors": [{"name": "Ben Brawn", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/605/"}]}