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Resultant force

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The cable stays AB and AD help support pole AC. Knowing that the tension is {tAB}N in AB and {tAD}N in AD,

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$\\tan \\alpha=\\frac{8}{10}\\quad\\Rightarrow\\quad \\alpha=\\var{gammaAB}^\\circ$ 

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$\\tan \\beta=\\frac{6}{10}\\quad\\Rightarrow\\quad \\beta=\\var{gammaAD}^\\circ$ 

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(a) Using the triangle rule

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$\\alpha+\\beta+\\psi=180^\\circ$

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$\\psi=180^\\circ-\\var{gammaAB}^\\circ-\\var{gammaAD}^\\circ=110.38^\\circ$

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Using the rule of cosines

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$R^2=T_{AB}^2+T_{AD}^2-2T_{AB}T_{AD}\\cos\\psi$

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$R^2=\\var{tAB}^2+\\var{tAD}^2-2(\\var{tAB})(\\var{tAD})\\cos 110.38^\\circ$

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$R=\\var{R}\\,\\text{N}$ \u25c0

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(b) Use the rule of sines 

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$\\dfrac{\\sin \\gamma}{T_{AD}}=\\dfrac{\\sin \\psi}{R}$

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$\\dfrac{\\sin \\gamma}{\\var{tAD}\\,\\text{N}}=\\dfrac{\\sin 110.38^\\circ}{\\var{R}\\,\\text{N}}$

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$\\gamma=\\var{a}^\\circ$ \u25c0

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Determine the magnitude of the resultant (in N) of the forces exerted by the stays at A using the triangle rule.

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What is the direction of the resultant force (measured from the stay AB in degrees) ?

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