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$\\cos\\theta = \\dfrac{e^{i\\theta} + e^{-i\\theta}}{2i}$
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Obtain the following relations by solving the equations
$e^{i\\theta} = \\cos{\\theta} +i\\sin{\\theta}$ and $e^{-i\\theta} = \\cos{\\theta} - i\\sin{\\theta}$
\nfor $\\sin{\\theta}$ and $\\cos\\theta$
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