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Friction

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The coefficient of friction between the block and the rail is $\\mu_s=\\var{mu_s}$. Knowing that $\\theta=\\var{th}^\\circ$, determine the smallest value of P (in N) required 

", "advice": "

$+\\!\\!\\nwarrow\\sum F_y=0,\\quad\\implies\\quad N-500 \\cos 35^\\circ+P\\sin(\\theta-35^\\circ)=0$

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$N=500 \\cos 35^\\circ-P\\sin( \\var{th-35}^\\circ),$

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$F_m=\\mu_s N$

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To start moving the block up the incline:

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$+\\!\\!\\swarrow\\sum F_x=0,\\quad\\implies\\quad \\mu_s N-P\\cos(\\theta-35^\\circ)+500\\sin 35^\\circ=0$

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$\\mu_s (500 \\cos 35^\\circ-P\\sin \\var{th-35}^\\circ)-P\\cos \\var{th-35}^\\circ+500\\sin 35^\\circ=0$

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$P=\\dfrac{500\\,(\\sin 35^\\circ+\\mu_s\\cos 35^\\circ)}{\\cos \\var{th-35}^\\circ+\\mu_s \\sin \\var{th-35}^\\circ}=\\var{Pmax}\\,\\text{N}\\quad\\blacktriangleleft$

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To prevent the block from moving down:

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$+\\!\\!\\swarrow\\sum F_x=0,\\quad\\implies\\quad -\\mu_s N-P\\cos(\\theta-35^\\circ)+500\\sin 35^\\circ=0$

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$-\\mu_s (500 \\cos 35^\\circ-P\\sin \\var{th-35}^\\circ)-P\\cos \\var{th-35}^\\circ+500\\sin 35^\\circ=0$

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$P=\\dfrac{500\\,(\\sin 35^\\circ-\\mu_s\\cos 35^\\circ)}{\\cos\\var{th-35}^\\circ-\\mu_s \\sin \\var{th-35}^\\circ}=\\var{Pmin}\\,\\text{N}\\quad\\blacktriangleleft$

\n

\\[\\var{Pmin}\\,\\text{N} \\le P \\le \\var{Pmax}\\,\\text{N}\\quad\\blacktriangleleft\\]

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to start the block moving up the rail, 

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to keep it from moving down.

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