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\\(Answer =\\) [[0]]

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Evaluate the following definite integral correct to three decimal places:

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\\(\\int_\\var{a}^\\var{b}\\var{m}sin^2(\\var{k}t)cos^2(\\var{k}t)dt\\)

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\\(\\int_\\var{a}^\\var{b}\\var{m}sin^2(\\var{k}t)cos^2(\\var{k}t)dt\\)

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\\(=\\int_\\var{a}^\\var{b}\\var{m}\\left(\\frac{1}{2}(1-cos(\\simplify{2*{k}}t))\\right)\\left(\\frac{1}{2}(1+cos(\\simplify{2*{k}}t))\\right)\\)

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\\(=\\int_\\var{a}^\\var{b}\\frac{\\var{m}}{4}\\left(1-cos(\\simplify{2*{k}}t)+cos(\\simplify{2*{k}}t)-cos^2(\\simplify{2*{k}}t)\\right)\\)

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\\(=\\int_\\var{a}^\\var{b}\\frac{\\var{m}}{4}\\left(1-cos^2(\\simplify{2*{k}}t)\\right)\\)

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\\(=\\int_\\var{a}^\\var{b}\\frac{\\var{m}}{4}sin^2(\\simplify{2*{k}}t)\\)

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\\(=\\int_\\var{a}^\\var{b}\\frac{\\var{m}}{4}\\frac{1}{2}\\left(1-cos(\\simplify{4*{k}}t)\\right)\\)

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\\(=\\frac{\\var{m}}{8}t-\\frac{\\var{m}}{\\simplify{32*{k}}}sin(\\simplify{4*{k}}t)\\Big|_\\var{a}^\\var{b}\\)

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\\(=\\frac{\\simplify{{m}*{b}}}{8}-\\frac{\\var{m}}{\\simplify{32*{k}}}sin(\\simplify{4*{k}*{b}})-\\frac{\\simplify{{m}*{a}}}{8}+\\frac{\\var{m}}{\\simplify{32*{k}}}sin(\\simplify{4*{k}*{a}})\\)

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