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Rearrange the following equation to make S the subject.

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$ V=\\frac{\\var{a}S}{S+\\var{b}}$

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Note: To write a fraction you type (numerator)/(denominator)

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S=[[0]]

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To transpose or rearrange a formula you may:

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Example: if y = x + 8,

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subtracting 8 yields

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y − 8 = x + 8 − 8

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y − 8 = x, thus changing the subject to X

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To transpose or rearrange a formula you may:

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1.In this part, take the denominator to the other side and

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2.Divide the right hand side by  A to get equation making 2 the subject

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Rearrange the equation by making 2 as the subject:

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$A=\\frac{bh}{2}$

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$2=\\frac{bh}{A}$

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$2=\\frac{A}{bh}$

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2= $A$ - $bh$

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2= $A$ + $bh$

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Rearrange the equation by making 'g' the subject of the formula:

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$\\displaystyle{\\frac{(f-\\var{i})^2}{(\\var{g}+\\var{i})}}=\\var{x}$

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$g=\\;$ [[0]]

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Note: To write a fraction, use (nominator)/ (denominator) and to square use '^2' sign

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1.Start by multiplying both sides by the denominator.

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2. Cancel out the like terms on either side of equation.

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3. Now expand out the brackets.

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4. Then collect the like terms on one side and the given subject on same side.

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5. Now you can factorise/solve using BIDMAS to get the answer in the given variable

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Rearrange the formula to make 'a' the subject:

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$\\ s =\\ u{t} + \\frac {\\var{r}}{\\var{k}} at^2$

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$a=\\;$ [[0]]

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Note: To write a fraction, use (nominator)/ (denominator) and to square use '^2' sign

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1.Start by taking the different variables to the other side, in this case - ut

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2.  Multiply the other side by 2 to cancel 2 from right side of equation.

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3. Now divide the whole term by t^2 to get the equation in terms of a.

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Rearrange the following equations in the given variable .

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For more help, check this video - https://www.youtube.com/watch?v=eTSVTTg_QZ4

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This exercise will help you rearrange some complex equations.

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To rearrange any formula or equation, follow these easy steps:

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1.Start by multiplying both sides by the denominator.

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2. Cancel out the like terms on either side of equation.

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3. Now expand out the brackets.

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4. Then collect the like terms on one side and the given subject on same side.

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5. Now you can factorise/solve using BIDMAS to get the answer in the given variable

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Example: In part a)

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1.Start by multiplying both sides by the denominator

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for example if you have $V=\\frac{\\var{a}S}{S+ \\var{b}}$ then multiply both sides by $(S+ \\var{b})$

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2.This gives:  $V(S+ \\var{b})=\\frac{\\var{a}S}{S+ \\var{b}} (S+ \\var{b}) $

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the $({ S+ \\var{b}})$ term on the right hand side cancels out to give: $V(S+ \\var{b})= \\var{a}S$

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3. Now expand out the brackets:  $VS+\\var{b}V= \\var{a}S$

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4. Then collect the like terms, you want to get all the terms with S in them onto one side, so subtract VS from both sides:

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$VS-VS+ \\var{b}V=\\var{a}S-VS$

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This becomes $\\var{b}V=\\var{a}S-VS$

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5. Now you can factorise the right hand side: $\\var{b}V=S(\\var{a}-V)$

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6. Then divide both sides by $({\\var{a} -V})$  to leave S on its own: $\\frac{\\var{b}V}{\\var{a}-V}=S$

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For more help, check this video- 

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