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Part a)

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Given $\\var{a}x+\\var{b}=\\var{c}$, we can start by subtracting $\\var{b}$ from both sides to get $\\var{a}x = \\simplify{{c-b}}$.

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Dividing both sides by $\\var{a}$ gives us $x= \\simplify {{c-b}/{a}}$

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Part b)

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We could start by subtracting $\\var{d}$ from both sides to get $-\\var{f}y = \\simplify{{g-d}}$.

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Or we could first add $\\var{f}y $ to both sides to get $\\var{d} = \\var{g} + \\var{f}y$. This avoids needing to divide by a negative number.

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Either way we should end up with $y= \\dfrac{\\simplify{{d- g}}}{\\var{f}}= \\simplify{{d-g}/{f}}$.

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Part c)

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$\\displaystyle{\\frac{z}{\\var{h}}}-\\var{j}=\\var{k}$ 

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$\\displaystyle{\\frac{z}{\\var{h}}}=\\var{k+j}$

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$z=\\var{ans3}$

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Part d)

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$\\displaystyle{\\frac{a-\\var{l}}{\\var{m}}}=\\var{n}$

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$a-\\var{l}=\\var{n*m}$

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$a=\\var{ans4}$

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Part e)

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$\\var{p}$$=$$\\var{q}(\\var{r}+b)$ 

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$\\displaystyle{\\simplify{{p}/{q}}}$$=$$\\var{r}+b$

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$\\displaystyle{\\simplify{{p-r*q}/{q}}}$$=$$b$

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Part f)

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$\\displaystyle{\\frac{\\var{s}w}{\\var{t}}}$$=$$\\var{u}$ 

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$\\var{s}w$$=$$\\var{u*t}$

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$w$$=$$\\displaystyle{\\simplify{{u*t}/{s}}}$

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For more help, check this video- 

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Solve the following equations. In each case give your answer to 2 decimal places.

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$x=$ [[0]].

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$\\var{d}-\\var{f}y=\\var{g}$

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$y=$ [[0]].

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$\\displaystyle{\\frac{z}{\\var{h}}}-\\var{j}=\\var{k}$

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$z=$ [[0]]

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$\\displaystyle{\\frac{a-\\var{l}}{\\var{m}}}=\\var{n}$.

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$a=$ [[0]]

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$\\var{p}=\\var{q}(\\var{r}+b)$.

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$b=$ [[0]]

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$\\displaystyle{\\frac{\\var{s}w}{\\var{t}}}=\\var{u}$.

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$w=$ [[0]]

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This exercise will help you solve equations of type ax-b = c.

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