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If \\[ A=\\left( \\begin{array}{ccc}
a & b & c \\\\d & e&f\\\\ g&h&j \\end{array} \\right),\\]
Cofactors are given by \\[ A=\\left( \\begin{array}{ccc}
a & b & c \\\\d & e&f\\\\ g&h&j \\end{array} \\right),\\]
Cof11 =\\[ +\\left| \\begin{array}{ccc}
e&f\\\\ h&j \\end{array} \\right|,\\]
Cof12 =\\[ -\\left| \\begin{array}{ccc}
d & f\\\\ g&j \\end{array} \\right|,\\]
Cof13 =\\[ +\\left| \\begin{array}{ccc}
d & e\\ g&h\\end{array} \\right|,\\]
Cof21 =\\[ -\\left| \\begin{array}{ccc}
b & c \\\\h&j \\end{array} \\right|,\\]
Cof22 =\\[ +\\left| \\begin{array}{ccc}
a & c \\\\ g&j \\end{array} \\right|,\\]
Cof23 =\\[ -\\left| \\begin{array}{ccc}
a & b \\\\g&h\\end{array} \\right|,\\]
Cof31 =\\[ +=\\left| \\begin{array}{ccc}
b & c \\\\e&f\\end{array} \\right|,\\]
Cof32 =\\[ -\\left| \\begin{array}{ccc}
a & c \\\\d & f\\end{array} \\right|,\\]
Cof33 =\\[ +\\left| \\begin{array}{ccc}
a & b\\\\d & e \\end{array} \\right|,\\]
Then, the determinant of A is given by the sum of the product of any row ( or column) elements by their cofactors
\ne.g row 1 determinant = a*cof11+b*cof12+c*cof13
\nand the inverse of A is given by the ratio of the adjoint(A) and the deteminant of A
\nwhere adjoint A= \\left( \\begin{array}{ccc}
cof11 & cof21 & cof31 \\\\cof12 & cof22&cof32\\\\ cof13&cof23&cof33 \\end{array} \\right),\\]
inverse of A=\\[ \\frac{1}{det(A)}*\\left( \\begin{array}{ccc}
cof11 & cof21 & cof31 \\\\cof12 & cof22&cof32\\\\ cof13&cof23&cof33 \\end{array} \\right),\\]
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Calculate the nine cofactors of A=$\\var{matrixA}$?
\n$A _{11}$ cofactor in position 1,1[[0]]
\n$A_{12}$ cofactor in position 1,2[[1]]
\n$A_{13}$ cofactor in position 1,3[[2]]
\n$A_{21}$ cofactor in position 2,1[[3]]
\n$A_{22}$ cofactor in position 2,2[[4]]
\n$A_{23}$ cofactor in position 2,3[[5]]
\n$A_{31}$ cofactor in position 3,1[[6]]
\n$A_{32}$ cofactor in position 3,2[[7]]
\n$A_{33}$ cofactor in position 3,3[[8]]
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\n[[0]]
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\n[[0]]
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