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\n

Using the rules of logs

\n

\\\begin{align}\\log_a(x^b)&=b\\log(x)\\\\ \\log_a(x)+\\log_a(y)&=\\log_a(xy)\\text{,}\\\\ \n \\log_a(x)-\\log_a(y)&=\\log_a\\left(\\frac{x}{y}\\right)\\text{.} \\end{align}\

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$\\log_a(\\var{x1[1]})+ \\log_a(\\var{x1[0]})=\\log_a($ [[0]]$)$

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$\\log_a(\\var{(x1[4])*y1})-\\log_a(\\var{x1[4]})=\\log_a($ [[0]]$)$

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Use laws for addition and subtraction of logarithms to simplify a given logarithmic expression to an arbitrary base.

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