// Numbas version: finer_feedback_settings {"name": "Peter's copy of statements with quantifiers and their negations", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"variable_groups": [], "statement": "

This question is about statements with quantifiers $\\forall$ and $\\exists$ and their negations.
The set of all integers is denoted by $\\mathbb Z$.

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  $\\exists z\\in \\mathbb Z~:~\\forall x\\in \\mathbb Z~:~x\\le z\\le 2 x $

", "

  $\\forall z\\in \\mathbb Z~:~\\exists x\\in \\mathbb Z~:~x\\le z\\le 2 x $

", "

  $\\forall x\\in \\mathbb Z~:~\\exists z\\in \\mathbb Z~:~ x\\le z\\le 2 x $

", "

  $\\exists x\\in \\mathbb Z~:~\\exists z\\in \\mathbb Z~:~x\\le z\\le 2 x $

"], "maxAnswers": "4", "prompt": "

Consider the following Statement 1:

\n

For every integer $x$ there is an integer $z$ such that $x\\le z\\le 2 x$.

\n

\n

Let us first rewrite this statement using mathematical notation for the sets and quantifiers.

\n

Which of the following is a correct formulation of Statement 1? Choose any that apply.

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 yes

", "

 no

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Let $x$ be an integer and consider the following Statement 2:

\n

$\\exists z\\in \\mathbb Z~:~ x\\le z\\le 2 x $

\n

Is Statement 2 correct if $x=0$?

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Is there some integer $x$ so that Statement 2 in b) is false?

\n

If not, enter $0$, otherwise give such an integer $x$ (you will get additional feedback in part d):

", "variableReplacementStrategy": "originalfirst", "showPrecisionHint": false}, {"matrix": ["0", "3"], "showCorrectAnswer": true, "shuffleChoices": false, "variableReplacements": [], "marks": 0, "minMarks": 0, "scripts": {}, "displayType": "radiogroup", "maxMarks": "3", "displayColumns": 0, "distractors": ["No, statement 1 is incorrect. If $x\\le 2x$, then a suitable $z$ so that $x\\le z\\le 2x~$ is, for example, $z=x$. So for the statement to be incorrect we need $\\neg(x\\le 2x)$, that is, $x>2x$, which (by subtracting $x$ on both sides) holds if and only if $0>x$. So any negative integer $x$ makes Statement 2 false and is therefore a counterexample to Statement 1.", "Statement 1 is indeed incorrect. If $x\\le 2x$, then a suitable $z$ so that $x\\le z\\le 2x~$ is, for example, $z=x$. So for the statement to be incorrect we need $\\neg(x\\le 2x)$, that is, $x>2x$, which (by subtracting $x$ on both sides) holds if and only if $0>x$. So any negative integer $x$ makes Statement 2 false and is therefore a counterexample to Statement 1."], "variableReplacementStrategy": "originalfirst", "type": "1_n_2", "choices": ["

 yes

", "

 no

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In view of your answer to c), is Statement 1 in a) above true?

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  For every integer $x$ there exists an integer $z$ such that $z<x$ or $z>2x$.

", "

  For every integer $z$ there exists an integer $x$ such that $z<x$ or $z>2x$.

", "

  There exists an integer $x$ such that there is an integer $z$ so that $z<x$ or $z>2x$.

", "

  There exists an integer $x$ such that for all integers $z$ we have $z<x$ or $z>2x$.

", "

  There exists an integer $x$ such that for all integers $z$ we have $x>z>2x$.

\n

"], "maxAnswers": "5", "prompt": "

We consider the negation of Statement 1 in a).

\n

Which of the following is a correct formulation of this negated statement? Choose any that apply.

"}, {"matrix": ["-4", "6", "-4", "-4", "-4"], "showCorrectAnswer": true, "shuffleChoices": true, "variableReplacements": [], "marks": 0, "minMarks": 0, "scripts": {}, "variableReplacementStrategy": "originalfirst", "warningType": "none", "displayType": "checkbox", "maxMarks": "6", "displayColumns": "1", "distractors": ["Incorrect, because $x\\le z\\le 2x$ stands for $(x\\le z)\\wedge (z\\le 2x)$ whose negation is $\\neg(x\\le z)\\vee \\neg(z\\le 2x)$.", "Correct! Note that $x\\le z\\le 2x$ stands for $(x\\le z)\\wedge (z\\le 2x)$ whose negation is $\\neg(x\\le z)\\vee \\neg(z\\le 2x)$.", "Incorrect. The negation of $\\exists z~P(z)$ is $\\forall z~\\neg P(z)$.", "Incorrect. The negation of $\\forall x~\\exists z~Q(x,z)~$ is $~\\exists x~\\forall z~\\neg Q(x,z)$.", "There are two mistakes here. The quantified variables $x$ and $z$ must appear in their original order, and $x\\le z\\le 2x$ stands for $(x\\le z)\\wedge (z\\le 2x)$ whose negation is $\\neg(x\\le z)\\vee \\neg(z\\le 2x)$."], "minAnswers": 0, "type": "m_n_2", "choices": ["

 $\\exists x\\in \\mathbb Z~:~\\forall z\\in \\mathbb Z~:~(z<x)\\wedge (z>2 x)$

", "

 $\\exists x\\in \\mathbb Z~:~\\forall z\\in \\mathbb Z~:~(z<x)\\vee (z>2 x)$ 

", "

  $\\exists x\\in \\mathbb Z~:~\\exists z\\in \\mathbb Z~:~(z<x)\\vee (z>2 x)$

", "

 $\\forall x\\in \\mathbb Z~:~\\exists z\\in \\mathbb Z~:~(z<x)\\vee (z>2 x)$

", "

  $\\exists z\\in \\mathbb Z~:~\\forall x\\in \\mathbb Z~:~x>z>2 x$

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Finally, find the correct formulation of the negation of Statement 1 in terms of mathematical symbols. Choose any that apply.

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Click on \"Show feedback\" after \"Submit part\" for detailed explanations.

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Example of a universal statement over the integers and its negation

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