This creates a 4x4 times table grid using numbers from 2 to 9. The step gives some advice on how to work out times tables (products, multiplications) if you can't remember them.

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$\\large\\var{r[0]}$ | [[0]] | [[1]] | [[2]] | [[3]] |

$\\large\\var{r[1]}$ | [[4]] | [[5]] | [[6]] | [[7]] |

$\\large\\var{r[2]}$ | [[8]] | [[9]] | [[10]] | [[11]] |

$\\large\\var{r[3]}$ | [[12]] | [[13]] | [[14]] | [[15]] |

Memorising as many of the times tables as possible is really helpful for lots of things in mathematics.

\nIf you can't memorise them, for some of the times tables there are little tricks you can use to work them out (sometimes quickly, sometimes slowly).

\n- \n
- Recall that the order of multiplication is irrelevant. For example, $8\\times 9$ is the same as $9\\times 8$ so sometimes thinking about the multiplication in the
**reverse order**makes it easier to recall or work out. \n - If you don't know a times table but you know one
**'near'**it, you can use that to work the unknown one out! For example, say you don't know $6\\times 7$, but you do know $6\\times 6=36$, then $6\\times 7$ is just one more lot of $6$, and so $6 \\times 7=36+6=42$. \n - As a last resort you can always just use
**repeated addition**. For example, for $8\\times 3$ you could just work out $8+8+8=16+8=24$, note this is less work than $8$ lots of $3$. \n - Multiply by $\\bf 2$. Most people are comfortable with doubling a number. If not, just add the number to itself. \n
- Multiplying by $\\bf 3$? You could just double it and add on another lot. For example, for $3\\times 7$ you could double $7$ then add another $7$ on, $3\\times 7=14+7=21$. \n
- Multiplying by $\\bf 4$? You could just double it and then double that. For example, for $4\\times 8$ you could double $8$ and get $16$ and then double $16$ to get $32$. \n
- Multiplying by $\\bf 5$? You could just multiply by $10$ (that is add on a zero) and then halve that. For example, for $5\\times 6$ you multiply $6$ by $10$ to get $60$ and then you halve $60$ to get $30$. \n
- Multiplying by $\\bf 6$? You could multiply by $5$ and then add one more lot on. For example, for $6\\times 8$ you could work out that $5\\times 8=40$ and then add on another $8$ to get $48$. \n
- Multiplying by $\\bf 7$? If you couldn't work it out another way, then you could multiply the number by $5$ and then add on the number doubled. For example, $7\\times 8=5\\times 8+2\\times 8=40+16=56$. \n
- Multiplying by $\\bf 8$? Here are three not-so-great ways (you can normally find a better way using the above tricks):\n
- \n
- Double, then double, then double. For example, for $8\\times 7$, double $7$ to get $14$, double that to get $28$, then double that to get $56$. \n
- Multiply the number by $5$ and $3$ separately and then add them up. For example, for $8\\times 7$ you could do $5\\times 7=35$ and $3\\times 7=21$ and so $8\\times 7=35+21=56$. \n
- Multiply the number by $10$ and then subtract the number doubled. For example, $8\\times 7$ will be $10\\times 7-2\\times 7=70-14=56$. \n

\n - Multiplying by $\\bf 9$? Here are two ways. \n
- \n
- You could multiply by $10$ (that is add on a zero) and then subtract one lot. For example, $9\\times 8=10\\times 8-8=80-8=72$. \n
- If you are multiplying $9$ by a number from $2$ to $10$ then take the number you are multiply by and subtract one from it, this is the start of your answer, then tack on whatever number makes the digits add up to $9$. For example, the answer to $9\\times 7$ starts the digit $6$ (one less than seven) and since $6+3=9$ the answer must be $9\\times 7=63$. \n

\n - Multiply by $\\bf 10$? Just add a zero to the end of the number. For example, $10\\times 7=70$. \n

If you are stuck on a times table, just for practice see if you can work it out in more than one way.

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\nFor more practice, click 'Try another question like this one'.

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