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Given $\\var{a}x=\\var{b}$, we can rearrange the equation to that find $x=$ [[0]].

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Given $\\var{a}x=\\var{b}$, we divide both sides by $\\var{a}$ to get $x$ by itself.

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$\\var{a}x$$=$$\\var{b}$
 
$\\displaystyle{\\frac{\\var{a}x}{\\var{a}}}$$=$$\\displaystyle{\\frac{\\var{b}}{\\var{a}}}$
 
$x$$=$$\\displaystyle{\\simplify{{b}/{a}}}$
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Given $\\var{c}y=\\var{d}$,  $y=$ [[0]].

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Given $\\var{c}y=\\var{d}$, we divide both sides by $\\var{c}$ to get $y$ by itself.

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$\\var{c}y$$=$$\\var{d}$
 
$\\displaystyle{\\frac{\\var{c}y}{\\var{c}}}$$=$$\\displaystyle{\\frac{\\var{d}}{\\var{c}}}$
 
$y$$=$$\\displaystyle{\\simplify{{d}/{c}}}$
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Rearrange $\\displaystyle{\\frac{z}{\\var{f}}}=\\var{g}$ to determine the value of $z$.

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$z=$ [[0]]

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Given $\\displaystyle{\\frac{z}{\\var{f}}}=\\var{g}$, we multiply both sides by $\\var{f}$ to get $z$ by itself.

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$\\displaystyle{\\frac{z}{\\var{f}}}$$=$$\\var{g}$
 
$\\displaystyle{\\frac{z}{\\var{f}}}\\times \\var{f}$$=$$\\var{g}\\times\\var{f}$
 
$z$$=$$\\var{ans3}$
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Solve $\\displaystyle{\\var{h}=-\\frac{a}{\\var{j}}}$ for $a$.

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$a=$ [[0]]

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Given $\\displaystyle{\\var{h}=-\\frac{a}{\\var{j}}}$, we multiply both sides by $-\\var{j}$ to get $a$ by itself.

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$\\var{h}$$=$$\\displaystyle{-\\frac{a}{\\var{j}}}$
 
$\\var{h}\\times(-\\var{j})$$=$$\\displaystyle{-\\frac{a}{\\var{j}}\\times(-\\var{j})}$
 
$\\var{ans4}$$=$$a$
 
$a$$=$$\\var{ans4}$
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