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5/08/2012:

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Added tags.

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Checked calculation.OK.

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Improved display in content areas.

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Solve for $x$: $\\displaystyle \\frac{a} {bx+c} + d= s$

", "licence": "Creative Commons Attribution 4.0 International"}, "advice": "

Rearrange the equation by adding {-c} to both sides to get:
\\[\\simplify{{t} / ({a} * x + {b}) = {d} + { -c} = {d -c}}\\]
This gives \\[\\simplify{({a} * x + {b}) / {t} = 1 / {d -c}}\\] (this is because if $\\displaystyle \\frac{a}{b}=c$ then $\\displaystyle \\frac{b}{a}=\\frac{1}{c}$ on turning the fraction round the other way)
and so \\[\\simplify{({a} * x + {b}) = {t} / {d -c}}\\] on multiplying both sides by {t}.
Hence \\[\\simplify{{a} * x = {t} / {d -c} -{b} = ({a * an1} / {an2})}\\]
and so \\[\\simplify{x={an1}/{an2}}\\] is the solution on dividing both sides by {a}.

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Input as a fraction or an integer, not as a decimal.

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\\[\\simplify{{t} / ({a} * x + {b}) + {c} = {d}}\\]

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$x=\\;$ [[0]]

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If you want help in solving the equation, click on \"Show steps\". If you do so then you will lose 1 mark.

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Input all numbers as fractions or integers and not as decimals.

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Rearrange the equation by adding {-c} to both sides to get:
\\[\\simplify[std]{{t} / ({a} * x + {b}) = {d} + { -c} = {d -c}}\\]

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This gives \\[\\simplify{({a} * x + {b}) / {t} = 1 / {d -c}}\\] (this is because if $\\displaystyle \\frac{a}{b}=c$ then $\\displaystyle \\frac{b}{a}=\\frac{1}{c}$ on turning the fraction round the other way)

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and so \\[\\simplify{({a} * x + {b}) = {t} / {d -c}}\\] on multiplying both sides by {t}.

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Solve this equation for $x$.

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Solve the following equation for $x$.

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Input your answer as a fraction or an integer as appropriate and not as a decimal.

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