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Crear una tabla de verdad para una expresión lógica de la forma:

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$$(a \\ {op1}\\,\\  b) \\ {op2}\\,\\ (c \\ {op3} \\,\\ d)$$

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donde $a, \\;b,\\;c,\\;d$ pueden variables booleanas $p,\\;q,\\;\\neg p,\\;\\neg q$  y cada operador  $\\operatorname{op1},\\;\\operatorname{op2},\\;\\operatorname{op3}$  es uno de los conectivos $\\lor,\\;\\land,\\;\\to$.

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Por ejemplo: $(p \\lor \\neg q) \\land(q \\to \\neg p)$.

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En la siguiente pregunta se pide que construya una tabla de verdad para:

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\\[(\\var{a} \\var{op} \\var{b})\\var{op1}(\\var{a1} \\var{op2} \\var{b1}).\\]

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Ingrese V si es verdadero, de lo contrario ingrese F.

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Primero encontramos la tabla de verdad para  $\\var{a} \\var{op} \\var{b}$:
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$p$$q$$\\var{a} \\var{op} \\var{b}$
$\\var{disp[0]}$$\\var{disq[0]}$$\\var{ev1[0]}$
$\\var{disp[1]}$$\\var{disq[1]}$$\\var{ev1[1]}$
$\\var{disp[2]}$$\\var{disq[2]}$$\\var{ev1[2]}$
$\\var{disp[3]}$$\\var{disq[3]}$$\\var{ev1[3]}$
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Entonces la tabla de verdad para $\\var{a1} \\var{op2} \\var{b1}$ es:

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$p$$q$$\\var{a1} \\var{op2} \\var{b1}$
$\\var{disp[0]}$$\\var{disq[0]}$$\\var{ev2[0]}$
$\\var{disp[1]}$$\\var{disq[1]}$$\\var{ev2[1]}$
$\\var{disp[2]}$$\\var{disq[2]}$$\\var{ev2[2]}$
$\\var{disp[3]}$$\\var{disq[3]}$$\\var{ev2[3]}$
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Colocando todo junto en una tabla para encontrar $(\\var{a} \\var{op} \\var{b})\\var{op1}(\\var{a1} \\var{op2} \\var{b1})$:

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$\\var{a} \\var{op} \\var{b}$$\\var{a1} \\var{op2} \\var{b1}$$(\\var{a} \\var{op} \\var{b})\\var{op1}(\\var{a1} \\var{op2} \\var{b1})$
$\\var{ev1[0]}$$\\var{ev2[0]}$$\\var{t_value[0]}$
$\\var{ev1[1]}$$\\var{ev2[1]}$$\\var{t_value[1]}$
$\\var{ev1[2]}$$\\var{ev2[2]}$$\\var{t_value[2]}$
$\\var{ev1[3]}$$\\var{ev2[3]}$$\\var{t_value[3]}$
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$p$$q$$\\var{a} \\var{op} \\var{b}$$\\var{a1} \\var{op2} \\var{b1}$$(\\var{a} \\var{op} \\var{b}) \\var{op1} (\\var{a1} \\var{op2} \\var{b1})$
$\\var{disp[0]}$$\\var{disq[0]}$[[0]][[4]][[8]]
$\\var{disp[1]}$$\\var{disq[1]}$[[1]][[5]][[9]]
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$\\var{disp[3]}$$\\var{disq[3]}$[[3]][[7]][[11]]
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