// Numbas version: exam_results_page_options {"name": "Luis's copy of Integration by partial fractions", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"ungrouped_variables": ["a", "c", "b", "s3", "s2", "s1", "b1"], "name": "Luis's copy of Integration by partial fractions", "variablesTest": {"condition": "", "maxRuns": 100}, "preamble": {"js": "", "css": ""}, "parts": [{"prompt": "\n\t\t\t

$I=\\;$[[0]]

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Input all numbers as fractions or integers and not decimals.

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Input the constant of integration as $C$.

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Click on Show steps for help if you need it. You will lose 1 mark if you do so.

\n\t\t\t", "gaps": [{"checkvariablenames": false, "showpreview": true, "vsetrangepoints": 5, "answersimplification": "std", "type": "jme", "expectedvariablenames": [], "scripts": {}, "marks": 3, "checkingaccuracy": 0.0001, "checkingtype": "absdiff", "answer": "({c}/{b-a})*(ln(x+{a})-ln(x+{b}))+C", "showCorrectAnswer": true, "vsetrange": [11, 12], "notallowed": {"message": "

Input all numbers as fractions or integers and not decimals.

", "strings": ["."], "showStrings": false, "partialCredit": 0}}], "steps": [{"type": "information", "prompt": "\n\t\t\t\t\t

First of all factorise the denominator.

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You have to find $a$ and $b$ such that $\\simplify[std]{x^2+{a+b}*x+{a*b}=(x+a)*(x+b)}$.

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Then use partial fractions to write:
\\[\\simplify[std]{{c}/((x +a)*(x+b)) = A/(x+a)+B/(x+b)}\\]

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for suitable integers or fractions $A$ and $B$.

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First we factorise $\\simplify[std]{x^2+{a+b}*x+{a*b}=(x+{a})*(x+{b})}$.

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You can do this by spotting the factors or by completing the square.

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Next we use partial fractions to find $A$ and $B$ such that:
\\[\\simplify[std]{{c}/((x +{a})*(x+{b})) = A/(x+{a})+B/(x+{b})}\\]
Multiplying both sides of the equation by $\\displaystyle \\simplify[std]{1/((x +{a})*(x+{b}))}$ we obtain:

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$\\simplify[std]{A*(x+{b})+B*(x+{a}) = {c}}\\Rightarrow \\simplify[std]{(A+B)x+{b}A+{a}B={c}}$

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Identifying coefficients:

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Constant term: $\\simplify[std]{{b}*A+{a}*B = {c}}$

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Coefficent $x$: $ \\simplify[std]{A + B = 0}$ which gives $A = -B$.

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Hence we obtain $\\displaystyle \\simplify[std]{A = {c}/{b-a}}$ and $\\displaystyle \\simplify[std]{B={-c}/{b-a}}$

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Which gives: \\[\\simplify[std]{{c}/((x +{a})*(x+{b})) = ({c}/{b-a})*(1/(x+{a}) -1/(x+{b}))}\\]

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So \\[\\begin{eqnarray*} I &=& \\simplify[std]{Int({c}/(x^2+{a+b}*x+{a*b}),x )}\\\\ &=& \\simplify[std]{Int({c}/((x +{a})*(x+{b})),x )}\\\\ &=& \\simplify[std]{({c}/{b-a})*(Int(1/(x+{a}),x) -Int(1/(x+{b}),x))}\\\\ &=& \\simplify[std]{({c}/{b-a})*(ln(x+{a})-ln(x+{b}))+C} \\end{eqnarray*}\\]

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Find the following integral.

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\\[I = \\simplify[std]{Int({c}/(x^2+{a+b}*x+{a*b}),x )}\\]

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Input all numbers as fractions or integers and not decimals.

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Input the constant of integration as $C$.

\n\t", "metadata": {"licence": "Creative Commons Attribution 4.0 International", "notes": "\n\t\t

5/08/2012:

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Added tags.

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Added description.

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Added decimal point as forbidden string.

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Note the checking range is chosen so that the arguments of the log terms are always positive - could have used abs - might be better?

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Improved display of Advice. 

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Added information about Show steps, also introduced penalty of 1 mark.

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Added !noLeadingMinus to ruleset std for display purposes.

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Factorise $x^2+bx+c$ into 2 distinct linear factors and then find $\\displaystyle \\int \\frac{a}{x^2+bx+c }\\;dx$ using partial fractions or otherwise.

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\n\t\t"}, "contributors": [{"name": "Newcastle University Mathematics and Statistics", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/697/"}, {"name": "Luis Hernandez", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/2870/"}]}]}], "contributors": [{"name": "Newcastle University Mathematics and Statistics", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/697/"}, {"name": "Luis Hernandez", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/2870/"}]}