// Numbas version: exam_results_page_options {"name": "Luis's copy of Indefinite integral of improper polynomial fraction", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"advice": "

Since the degree of the numerator of $f(x)$ is greater than the denominator, $f(x)$ is improper.

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First, perform a division in whatever way you like, so that $f(x)$ can be rewritten in the form $\\displaystyle{f(x)=\\simplify[std]{{n}x+{m}+{p}/(1+x^2)}}$.

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Each term of this expression can then be integrated using standard functions (to within the arbitrary constant) to give:

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$\\displaystyle{\\int f(x)\\;dx=\\simplify[std]{{n}x^2/2+{m}x+{p}arctan(x)} +C}$

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Integrate the following function $f(x)$

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\\[f(x)=\\simplify[std]{({n}x^3+{m}x^2+{n}x +{m+p})/(1+x^2)}\\]

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Note that you can only enter inverse trigonometric functions as $\\arcsin(x),\\;\\;\\arccos(x),\\;\\;\\arctan(x)$

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Input all numbers as fractions or integers and not decimals.

", "parts": [{"prompt": "

$\\displaystyle \\int f(x)\\;dx=\\;\\;$[[0]]

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Input the arbitrary constant of integration as $C$.

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Input all numbers as fractions or integers and not decimals.

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29/06/2012:

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Added tags. Tidied up display of prompt.

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19/07/2012:

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Added description.

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Checked calculation.

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Slight change to Advice, replaced \"long division\" by \"whatever way you like\" so not to prempt the method used by the student.

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23/07/2012:

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Solution always requires arctan(x) and not arcsin(x) or arccos(x). Is this on purpose?

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Question appears to be working correctly.

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", "description": "

Find $\\displaystyle \\int \\frac{nx^3+mx^2+nx + p}{1+x^2}\\;dx$. Solution involves $\\arctan$.

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