See all the lectures and workshops up to this point.

", "metadata": {"description": "15 questions based on module so far.

", "licence": "Creative Commons Attribution 4.0 International"}, "variablesTest": {"condition": "", "maxRuns": 100}, "statement": "This is a non-calculator question.

", "ungrouped_variables": [], "variables": {"c": {"definition": "random(6..9)", "description": "", "templateType": "anything", "name": "c", "group": "change these"}, "statements_true": {"definition": "[\"$\\\\log(ab) = \\\\log(a)+\\\\log(b)$\",\n\"$\\\\sin(ab) \\\\neq \\\\sin(a) \\\\sin(b)$\",\n\"$\\\\sqrt{ab} = \\\\sqrt{a}\\\\sqrt{b}$\",\n\"$e^{a+b} = e^ae^b$\",\n\"$\\\\dfrac{\\\\sqrt{a}}{b} = \\\\sqrt{\\\\dfrac{a}{b^2}}$\",\n\"'$ ^nC_r$' is pronounced '$n$ choose $r$ ' \",\n\"'$ n!$' is pronounced '$n$ factorial ' \",\n\"If $h$ is a small number, then $h^2$ is even smaller\",\n\"Unlike Maths 1, next semester the CLEs in Maths 2 will have weekly deadlines\",\n\"$ \\\\dfrac{6!}{3!} = 6 \\\\cdot 5 \\\\cdot 4$\",\n\"To get from a graph of $f(x)$ to a graph of $f(x)+3$, you translate up by 3\",\n\"To get from a graph of $f(x)$ to a graph of $f(x+3)$, you translate left by 3\",\n\"To get from a graph of $f(x)$ to a graph of $f(x-3)$, you translate right by 3\",\n\"To get from a graph of $f(x)$ to a graph of $3*f(x)$, you stretch vertically by a factor of 3\",\n\"To get from a graph of $f(x)$ to a graph of $f(3x)$, you compress horizontally by a factor of 3\",\n\"To get from a graph of $f(x)$ to a graph of $f(\\\\frac{1}{3}x)$, you stretch horizontally by a factor of 3\"\n]\n ", "description": "[\"$\\\\log(ab) = \\\\log(a)+\\\\log(b)$\",

\"$\\\\sin(ab) \\\\neq \\\\sin(a) \\\\sin(b)$\",

\"$\\sqrt(ab) = \\\\sqrt(a)\\\\sqrt(b)$\",

\"$e^{ab} = e^ae^b$\",

\n\"$\\\\dfrac{\\\\sqrt{a}}{b} = \\\\sqrt{\\\\dfrac{a}{b^2}}$\",

\n\"'$ ^nC_r$' is pronounced '$n$ choose $r$ ' \",

\n\"'$ n!$' is pronounced '$n$ factorial ' \",

\n\"If $h$ is a small number, then $h^2$ is even smaller\",

\n\"Unlike Maths 1, next semester the CLEs in Maths 2 will have weekly deadlines\",

\n\"$ \\\\dfrac{6!}{3!} = 6 \\\\cdot 5 \\\\cdot 4$\",

\n\"To get from a graph of $f(x)$ to a graph of $f(x)+3$, you translate up by 3\",

\n\"To get from a graph of $f(x)$ to a graph of $f(x+3)$, you translate left by 3\",

\n\"To get from a graph of $f(x)$ to a graph of $f(x-3)$, you translate right by 3\",

\n\"To get from a graph of $f(x)$ to a graph of $3*f(x)$, you stretch vertically by a factor of 3\",

\n\"To get from a graph of $f(x)$ to a graph of $f(3*x)$, you compress horizontally by a factor of 3\"

]

True

", "False

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", "showCorrectAnswer": true, "shuffleChoices": true, "shuffleAnswers": false, "displayType": "radiogroup", "maxMarks": "0", "layout": {"expression": "", "type": "all"}}], "name": "CLE8. True false", "tags": [], "type": "question", "contributors": [{"name": "Lovkush Agarwal", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/1358/"}]}]}], "contributors": [{"name": "Lovkush Agarwal", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/1358/"}]}