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Order of Operations

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rebelmaths

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Calculate the following.

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Remember the order of operations

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B Brackets

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O pOwers

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D Division

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M Multiplication

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A Addition

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S Subtraction

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a)

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First do the calculations $\\displaystyle \\simplify[all,!simplifyFractions]{{a4}/{a5}={a4/a5}}$ and $\\simplify[all,!collectNumbers]{{a2}*{a3}={a2*a3}}$.

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and then we get

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\\[\\begin{align} \\simplify[all,!collectNumbers,!simplifyFractions]{{a1}+ {a2}{a3}+{a4}/{a5}}&=\\simplify[all,!collectNumbers,!simplifyFractions]{{a1}+ {a2*a3}+{a4/a5}}\\\\&=\\var{ans1}\\end{align}\\]

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b)

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First do the calculations  $\\displaystyle \\simplify[all,!collectNumbers,!simplifyFractions]{{b1}/{b2}={b1/b2}} \\text{ and }  \\simplify[all,!collectNumbers]{{b3}({b4}+{b5})={b3}{b4+b5}={b3*(b4+b5)}}$

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and then we get

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\\[\\begin{align} \\simplify[all,!collectNumbers,!simplifyFractions]{{b1}/{b2}+{b3}*({b4}+{b5}){b6}+{b7}}&=\\simplify[all,!collectNumbers]{{b1/b2}+{b3*(b4+b5)}+{b7}}\\\\&=\\var{ans2}\\end{align}\\]

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c)

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First do the calculations  $\\displaystyle \\simplify[all,!collectNumbers,!simplifyFractions]{({c4}+{c5})/{c6}={c4+c5}/{c6}={(c4+c5)/c6}} \\text{ and }  \\simplify[all,!collectNumbers]{{c1}({c2}+{c3})={c1}{c2+c3}={c1*(c2+c3)}}$

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and then we get

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\\[\\begin{align} \\simplify[all,!collectNumbers,!simplifyFractions]{{c1}*({c2}+{c3})+({c4}+{c5})/{c6}}&=\\simplify[all,!collectNumbers]{{c1*(c2+c3)}+{(c4+c5)/c6}}\\\\&=\\var{ans3}\\end{align}\\]

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$\\displaystyle \\simplify[all,!collectNumbers,!simplifyFractions]{{a1}+ {a2}{a3}+{a4}/{a5}}=\\;$[[0]]

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$\\displaystyle \\simplify[all,!simplifyFractions,!collectNumbers]{{b1}/{b2}+{b3}({b4}+{b5}){b6}+{b7}}=\\;$[[0]]

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$\\displaystyle \\simplify[all,!collectNumbers,!simplifyFractions]{{c1}({c2}+{c3})+({c4}+{c5})/{c6}}=\\;$[[0]]

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