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$\\var{n[0]*index[0]}$, $\\var{n[0]*(index[0]+1)}$, $\\var{n[0]*(index[0]+2)}$, $\\var{n[0]*(index[0]+3)}$

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Diferencia Común= [[0]]

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$\\var{n[1]*(index[1])}$, $?$, $\\var{n[1]*(index[1]+2)}$, $?$, $\\var{n[1]*(index[1]+4)}$

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Diferencia Común = [[0]]

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$\\var{n[2]*(index[2])}$, $?$, $?$, $\\var{n[2]*(index[2]+3)}$, $?$, $?$, $\\var{n[2]*(index[2]+6)}$

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diferencia Común = [[0]]

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Encuentra las diferencias comunes de las siguientes secuencias aritméticas. Faltan algunos de los términos.

", "ungrouped_variables": ["n", "index"], "extensions": [], "advice": "

En una secuencia aritmética, la diferencia entre dos términos adyacentes es siempre la misma.

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Llame a la diferencia común $d$ y al primer término en la secuencia $a_0$. Entonces la secuencia es la siguiente:

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\\[ a_0, \\; a_0+d, \\; a_0+2d, \\; a_0+3d, \\; \\ldots \\]

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La diferencia entre un término en la secuencia y el término de lugar $n$  es $n\\times d$.

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a)

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La diferencia entre los dos primeros términos es $\\var{n[0]*(index[0]+1)} - \\var{n[0]*index[0]} = \\var{n[0]}$.

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Así que la diferencia común es $\\var{n[0]}$.

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b)

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No se nos da ningún término adyacente de esta secuencia, pero se nos dan algunos términos separados dos espacios.

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\\begin{align}
2d &= \\var{n[1]*(index[1]+2)} - \\var{n[1]*index[1]} \\\\
&= \\var{2*n[1]} \\\\
d &= \\var{n[1]}
\\end{align}

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La diferencia común es $\\var{n[1]}$.

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c)

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Nuevamente, no tenemos términos adyacentes de esta secuencia, pero tenemos dos términos separados por tres lugares.

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\\begin{align}
3d &= \\var{n[2]*(index[2]+3)} - \\var{n[2]*index[2]} \\\\
&= \\var{3*n[2]} \\\\
d &= \\var{n[2]}
\\end{align}

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La diferencia común es$\\var{n[2]}$.

\n

", "name": "Encontrar la diferencia com\u00fan en una Secuencia Aritm\u00e9tica", "metadata": {"description": "

Dadas las secuencias con términos faltantes, encuentra la diferencia común entre los términos.

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