// Numbas version: finer_feedback_settings {"name": "Resuelve las operaciones de n\u00fameros complejos y expresa en la forma $ a + bi \\; $ donde $ a $ y $ b $ son reales.", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "Resuelve las operaciones de n\u00fameros complejos y expresa en la forma $ a + bi \\; $ donde $ a $ y $ b $ son reales.", "tags": [], "metadata": {"description": "
Multiplicación y suma de números complejos.
", "licence": "Creative Commons Attribution 4.0 International"}, "statement": "Resuelve las operaciones de números complejos y expresa en la forma $ a + bi \\; $ donde $ a $ y $ b $ son reales.
\nIngresa todos los números como fracciones o enteros. No incluya corchetes en su respuesta. Recuerda que $i^2=-1$
", "advice": "a)
\nLa solución está dada por:
\n
$\\simplify[std]{{e6*i}}(\\simplify[std]{{a}})=\\simplify[std]{{a*e6*i}}$
b)
$\\simplify[std]{{a}*{z4}={a*z4}}$
\n
c)
\\[ \\begin{eqnarray*} \\simplify[std,!otherNumbers]{{a}*({a3} + {b3} * i + {c3} * i ^ 2 + {d3} * i ^ 3)}&=&\\simplify[std]{{a}*{a3 + b3 * i + c3 * i ^ 2 + d3 * i ^ 3}}\\\\ &=&\\simplify[std]{{a*(a3 + b3 * i + c3 * i ^ 2 + d3 * i ^ 3)}} \\end{eqnarray*} \\]
d)
Esto se puede calcular usando la fórmula dos veces, primero para multiplicar los dos primeros conjuntos de paréntesis,
\ny luego multiplicar el resultado de ese cálculo por el tercer conjunto de paréntesis.
\n\nAsi obtenemos:
\\[ \\begin{eqnarray*} (\\var{a})(\\var{z1})(\\var{z3})&=&((\\var{a})(\\var{z1}))(\\var{z3})\\\\ &=&(\\var{a*(z1)})(\\var{z3})\\\\ &=&\\var{a*(z1)*(z3)} \\end{eqnarray*} \\]
$\\var{e6*i}(\\simplify[std]{{a}})\\;=\\;$[[0]].
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