// Numbas version: finer_feedback_settings {"name": "Resuelve las operaciones de n\u00fameros complejos y expresa en la forma $ a + bi \\; $ donde $ a $ y $ b $ son reales.", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "Resuelve las operaciones de n\u00fameros complejos y expresa en la forma $ a + bi \\; $ donde $ a $ y $ b $ son reales.", "tags": [], "metadata": {"description": "

Multiplicación y suma de números complejos.

", "licence": "Creative Commons Attribution 4.0 International"}, "statement": "

Resuelve las operaciones de números complejos y expresa en la forma $ a + bi \\; $ donde $ a $ y $ b $ son reales.

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Ingresa todos los números como fracciones o enteros. No incluya corchetes en su respuesta. Recuerda que $i^2=-1$

", "advice": "

a)

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La solución está dada por:

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$\\simplify[std]{{e6*i}}(\\simplify[std]{{a}})=\\simplify[std]{{a*e6*i}}$

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b)

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$\\simplify[std]{{a}*{z4}={a*z4}}$

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c)
\\[ \\begin{eqnarray*} \\simplify[std,!otherNumbers]{{a}*({a3} + {b3} * i + {c3} * i ^ 2 + {d3} * i ^ 3)}&=&\\simplify[std]{{a}*{a3 + b3 * i + c3 * i ^ 2 + d3 * i ^ 3}}\\\\ &=&\\simplify[std]{{a*(a3 + b3 * i + c3 * i ^ 2 + d3 * i ^ 3)}} \\end{eqnarray*} \\]
d)

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Esto se puede calcular usando la fórmula dos veces, primero para multiplicar los dos primeros conjuntos de paréntesis,

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y luego multiplicar el resultado de ese cálculo por el tercer conjunto de paréntesis.

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Asi obtenemos:
\\[ \\begin{eqnarray*} (\\var{a})(\\var{z1})(\\var{z3})&=&((\\var{a})(\\var{z1}))(\\var{z3})\\\\ &=&(\\var{a*(z1)})(\\var{z3})\\\\ &=&\\var{a*(z1)*(z3)} \\end{eqnarray*} \\]

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$\\var{e6*i}(\\simplify[std]{{a}})\\;=\\;$[[0]].

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$(\\simplify[std]{{a}})(\\simplify[std]{{z4}})\\;=\\;$[[0]].

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$\\simplify[std,!otherNumbers]{{a}*({a3} + {b3} * i + {c3} * i ^ 2 + {d3} * i ^ 3)}\\;=\\;$[[0]].

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$(\\simplify[std]{{a}})(\\simplify[std]{ {z1}})(\\simplify[std]{ {z3}})\\;=\\;$[[0]].

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