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Cálculo del módulo, argumento, multiplicación por conjugado complejo, dados dos números complejos.

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Dados los números complejos $ z_1 = \\var {z1} $ y $ z_2 = \\var {z2} $.

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Calcule las siguientes cantidades. En lo que sigue, un asterisco denota el conjugado complejo.

", "advice": "

a) and b)

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El módulo de un número complejo $z=a+bi$ esta dado por 

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\\[\\lvert z \\rvert=\\sqrt{a^2+b^2}\\]

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En esta parte, $z_1 = \\var{z1}$ and $z_2 = \\var{z2}$, así

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\\begin{align}
\\lvert z_1 \\rvert &=\\sqrt{(\\var{re(z1)})^2+(\\var{im(z1)})^2} \\\\
&= \\var{absz1}
\\end{align}

\n

y

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\\begin{align}
\\lvert z_2 \\rvert &= \\sqrt{(\\var{re(z2)})^2+(\\var{im(z2)})^2} \\\\
&= \\var{absz2}
\\end{align}

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(ambos con 3 decimales).

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c)

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En general

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\\[\\lvert z_1z_2 \\rvert=\\lvert z_1 \\rvert\\lvert z_2 \\rvert\\]

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Asi, en esta parte,

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\\[ \\lvert z_1z_2 \\rvert=\\sqrt{(\\var{re(z1)})^2+(\\var{im(z1)})^2}\\sqrt{(\\var{re(z2)})^2+(\\var{im(z2)})^2}=\\var{absz1z2} \\]

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Considerar hasta 3 decimales.

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d)

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Si $z=a+bi$, then $z^\\ast=a-bi$, entonces

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\\[z_1^\\ast=\\var{conjz1}\\]

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e)

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En general, $zz^\\ast=(a+bi)(a-bi)=a^2+b^2$, asi

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\\[z_1z_1^\\ast=(\\var{z1})(\\var{conjz1})=(\\var{re(z1)})^2+(\\var{im(z1)})^2=\\var{z1conjz1}.\\]

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$\\lvert z_1 \\rvert=$ [[0]] (Ingrese su respuesta con 3 decimales)

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$\\lvert z_2 \\rvert=$ [[0]] (Ingrese su respuesta con 3 decimales)

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$\\lvert z_1z_2 \\rvert=$ [[0]] (Ingrese su respuesta con 3 decimales)

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$z_1^\\ast=$ [[0]]

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$z_1z_1^\\ast=$ [[0]]

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