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Consider the following recurrence relation:

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\\[C(n)=\\begin{cases}\\var{b} & if & n=1\\\\ \\var{a}C(n-1) & if & n\\geq2 \\end{cases}\\]

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Compute the first six terms of this recurrence relation.

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C(1) = [[0]]

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C(2) = [[1]]

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C(3) = [[2]]

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C(4) = [[3]]

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C(5) = [[4]]

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C(6) = [[5]]

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Write $C(\\var{c})$ in terms of $C(\\var{d})$

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$C(\\var{c}) = C(\\var{d}) \\times $[[0]]

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Write $C(\\var{c})$ in terms of $C(\\var{f})$

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$C(\\var{c}) = C(\\var{f}) \\times $ [[0]]

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