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Remember to give all answers to the nearest penny as requested.

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First calculate $\\var{num}$% of the estimate $\\var{est}$

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$\\frac{\\var{num}}{100} \\times \\var{est} = £\\var{dpformat(per,2)}$

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(a)

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Cheapest possible cost

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$£\\var{est} - £\\var{dpformat(per,2)} = £\\var{dpformat(ans1,2)}$

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(b)

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Dearest possible cost

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$£\\var{est} + £\\var{dpformat(per,2)} = £\\var{dpformat(ans2,2)}$

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The actual cost must be in the range $\\var{est} \\pm \\var{num}$%. So first we must work out $\\var{num}\\% $ of $\\var{est}$. 

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Calculate the cheapest and most expensive possible costs, if an estimate of $£\\var{est}$ is given for a particular repair.

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Cheapest:    £[[0]]

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Most expensive:      £[[1]]

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(Calculate the minimum and maximum approximations of an estimate)

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rebelmaths

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$\\var{shop}$ guarantees that the actual cost of repairs will not be more than $\\var{num}$% different from any estimate.

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Give your final answer correct to the nearest penny.

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