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Ratio of sides of rectangles

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rebel

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rebelmaths

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Suppose the original rectangle has length $l$ and width $w$. This has area $w\\times l$.

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The new rectangle has length $\\var{sf}l$ and width $\\var{sf}w$. What is it's area? How does this relate to the original rectangle?

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The length and width of a rectangle are both mutiplied by $\\var{sf}$ 

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What must we multiply the old area by to find the new area?

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Suppose the original rectangle has length $l$ and width $w$. This has area $w\\times l$.

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The new rectangle has length $l\\times(1+\\var{numberone/100})$ and width $w\\times(1-\\var{numbertwo/100})$. What is it's area? How does this relate to the original rectangle?

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The length of a rectangle is increased by $\\var{numberone}$% while the width is decreased by $\\var{numbertwo}$%.

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What must we multiply the old area by to find the new area?

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[[0]]

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(a)

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Suppose the original rectangle has length $l$ and width $w$. This has area $w\\times l$.

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The new rectangle has length $\\var{sf}l$ and width $\\var{sf}w$. 

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Therefore it has area $\\var{sf}w \\times \\var{sf}l = \\var{sf}^2\\times w \\times l$, which is $\\var{sf^2}$ times the original area.

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In general:

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-if we enlarge a 2-d shape by scale factor $k$, its area will be multiplied by $k^2$

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-if we enlarge a 3-d shape by scale factor $k$, its volume will be multiplied by $k^3$

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(b)

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An increase in length of $\\var{numberone}$%, is the same as multiplying the length by $\\var{lent}$

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An decrease in width of $\\var{numbertwo}$%, is the same as multiplying the width by $\\var{width}$

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Therefore the new area will be $\\var{width}w \\times \\var{lent}l = \\var{width*lent}\\times w \\times l$

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