// Numbas version: exam_results_page_options {"name": "Blathnaid's copy of Simon's copy of Q3 Indices; Solve for x", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"metadata": {"description": "
Indices
\nrebelmaths
", "licence": "Creative Commons Attribution 4.0 International"}, "tags": [], "ungrouped_variables": ["num11", "num12", "num13", "nn1", "p1", "ans1", "num21", "num22", "p21", "p22", "nn21", "nn22", "ans2", "p31", "p32", "num31", "num32", "ans3", "p41", "p42", "num41", "num42", "num43", "ans4", "nn31", "nn32", "nn41", "nn42"], "rulesets": {}, "statement": "Solve for $x$ in each of the following:
\nEnter answer as a whole number or fraction
", "variablesTest": {"condition": "ans1<100 and ans2<100 and ans3<100 and ans4<100", "maxRuns": 100}, "advice": "(a)
\n$2^{\\var{num11}x-\\var{num12}} = \\var{nn1}^{x+\\var{num13}}$
\n$2^{\\var{num11}x-\\var{num12}}= (2^\\var{log({nn1},2)})^{x+\\var{num13}}$
\n$2^{\\var{num11}x-\\var{num12}}= 2^{\\var{log({nn1},2)}(x+\\var{num13})}$
\n$\\implies \\var{num11}x-\\var{num12} = \\var{log({nn1},2)}(x+\\var{num13})$
\n$\\implies \\var{num11}x-\\var{num12} = \\var{log({nn1},2)}x +\\var{log({nn1},2)*num13}$
\n$\\implies \\var{num11-log({nn1},2)}x = \\var{num12+log({nn1},2)*num13}$
\n$\\implies x = \\var{(num12+log({nn1},2)*num13)/(num11-log({nn1},2))}$
\n\n(b)
\n\n
$(3^\\var{log({nn21},3)})^{x-\\var{num21}} = (3^\\var{log({nn22},3)})^{\\var{num22} - x}$
\n$3^{\\var{log({nn21},3)}({x-\\var{num21}})} =3^{\\var{log({nn22},3)}({\\var{num22} - x})}$
\n$\\implies \\var{log({nn21},3)}({x-\\var{num21}}) ={\\var{log({nn22},3)}({\\var{num22} - x})} $
\n$\\implies \\var{log({nn21},3)} x-\\var{log({nn21},3)*num21} =\\var{log({nn22},3)*{num22}} -\\var{log({nn22},3)} x $
\n$\\implies \\var{log({nn21},3)+log({nn22},3)} x =\\var{log({nn22},3)*{num22} +log({nn21},3)*num21} $
\n$\\implies x =\\var{(log({nn22},3)*{num22}+log({nn21},3)*num21)/(log({nn21},3)+log({nn22},3))} $
\n\n\n(c)
\n$\\var{nn31}^{\\var{num31}x+\\var{num32}} = \\frac{1}{\\var{nn32}}$
\n$(2^\\var{log(nn31,2)})^{\\var{num31}x+\\var{num32}}= \\var{2}^{-\\var{log({nn32},2)}}$
\n$2^{\\var{log(nn31,2)}({\\var{num31}x+\\var{num32}})}= \\var{2}^{-\\var{log({nn32},2)}}$
\n$\\implies \\var{log(nn31,2)}({\\var{num31}x+\\var{num32}})= -\\var{log({nn32},2)}$
\n$\\implies \\var{log(nn31,2)*{num31}}x+\\var{log(nn31,2)*num32}=-\\var{log({nn32},2)}$
\n$\\implies x=\\frac{-\\var{log({nn32},2)}-\\var{log(nn31,2)*num32}}{\\var{log(nn31,2)*{num31}}}=\\var{(-log({nn32},2)-log(nn31,2)*num32)/(log(nn31,2)*{num31})}$
\n\n\n(d)
\n$\\var{nn41}^{\\var{num41}x-\\var{num42}} = \\var{nn42}^{\\var{num43} - x}$
\n$(5^\\var{log({nn41},5)})^{\\var{num41}x-\\var{num42}} = (5^\\var{log({nn42},5)})^{\\var{num43} - x}$
\n$5^{\\var{log({nn41},5)}({\\var{num41}x-\\var{num42}})} =5^{\\var{log({nn42},5)}({\\var{num43} - x})}$
\n$\\implies \\var{log({nn41},5)}({\\var{num41}x-\\var{num42}}) ={\\var{log({nn42},5)}({\\var{num43} - x})} $
\n$\\implies \\var{log({nn41},5)*num41} x-\\var{log({nn41},5)*num42} =\\var{log({nn42},5)*{num43}} -\\var{log({nn42},5)} x $
\n$\\implies \\var{log({nn41},5)*num41+log({nn42},5)} x =\\var{log({nn42},5)*{num43} +log({nn41},5)*num42} $
\n$\\implies x =\\var{(log({nn42},5)*{num43}+log({nn41},5)*num42)/(log({nn41},5)*num41+log({nn42},5))} $
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\n$x =$ [[0]]
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\n$x=$ [[0]]
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