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Find the $x$ and $y$ components of a force which is applied at an angle to a particle. Resolve using $F \\cos \\theta$. The force is applied in the negative $x$ and negative $y$ direction.

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$F = \\var{force} \\, \\mathrm{N}$ at an angle of $\\theta = \\var{theta}^{\\circ}$ from the downwards vertical line. 

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Give your answers to the following questions to 3 decimal places.

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a)

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We need to find the angle $\\theta_x$ of $F$ relative to the $x$-axis and then use $F \\times cos\\theta_x$.

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We consider the angle between the positive $x$-axis and $F$, i.e. $\\theta_x = 90 + \\var{theta}$.

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\\begin{align}
\\text{component in the } x \\text{-direction} & = F \\cos\\theta_x \\\\
& = \\var{force} \\times \\cos \\var{angle} \\\\
& = \\var{precround(force*cos(radians(angle)),3)}
\\end{align}

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b)

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The positive $y$-direction is vertically upwards and we need the angle relative to the positive $y$-direction therefore $\\theta_y = 180 - \\var{theta}$.

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\\begin{align}
\\text{component in the } y \\text{-direction} & = F \\cos\\theta_y \\\\
& = \\var{force} \\times \\cos \\var{yangle} \\\\
& = \\var{precround(force*cos(radians(yangle)),3)}
\\end{align}

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Notice that both these answers are negative as the force acts in the opposite direction to the positive.  

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Find the component of the force in the $x$-direction in Newtons.

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Find the component of the force in the $y$-direction in Newtons.

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