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$A={\\rm log(\\frac{{\\it {I}}_0}{{\\it {I}}_t})}=\\varepsilon ~c~l$

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The molar absorption coefficient, $\\epsilon$ of a solute at 540 nm is {epsilon} mol-1 dm3 cm-1 . When light of that wavelength passes through a {l} mm cell containing a solution of the solute, the transmitted light intensity, It, is {it} % of I0

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\\[A={\\rm log(\\frac{{\\it{I}}_0}{{\\it {I}}_t})}=\\varepsilon ~c~l\\]

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Where

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\\[I_t=\\var{it}\\% \\]

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\\[~\\]

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Substitute into \\[A={\\rm log(\\frac{{\\it I}_o}{{\\it I}_t})}=\\varepsilon~c~l\\]

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\\[I_{\\rm 0} ~\\rm is~ \\therefore ~100~\\% ~relative ~to~ the~ observed ~ray\\]

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\\[A={\\rm log(\\frac{\\var{io}}{\\var{it}})}=\\var{a}\\ \\]

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What is the absorbance, A, of the solution?

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