// Numbas version: finer_feedback_settings {"name": "Simon's copy of Rearrange equations", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"variables": {"a": {"name": "a", "group": "Ungrouped variables", "definition": "random(2..8)", "templateType": "anything", "description": ""}, "b": {"name": "b", "group": "Ungrouped variables", "definition": "random(5..16)", "templateType": "anything", "description": ""}}, "parts": [{"variableReplacementStrategy": "originalfirst", "gaps": [{"checkingaccuracy": 0.001, "answer": "({b}*V)/({a}-V)", "marks": "5", "variableReplacements": [], "showCorrectAnswer": true, "vsetrangepoints": 5, "scripts": {}, "checkvariablenames": false, "showpreview": true, "expectedvariablenames": [], "vsetrange": [0, 1], "checkingtype": "absdiff", "variableReplacementStrategy": "originalfirst", "type": "jme"}], "type": "gapfill", "marks": 0, "prompt": "

Rearrange the following equation to make S the subject.

\n

\n

$ V=\\frac{\\var{a}S}{S+\\var{b}}$

\n

\n

to write a fraction you type (numerator)/(denominator)

\n

S=[[0]]

\n

", "variableReplacements": [], "showCorrectAnswer": true, "scripts": {}}], "functions": {}, "ungrouped_variables": ["a", "b"], "showQuestionGroupNames": false, "question_groups": [{"name": "", "pickingStrategy": "all-ordered", "pickQuestions": 0, "questions": []}], "name": "Simon's copy of Rearrange equations", "preamble": {"css": "", "js": ""}, "metadata": {"description": "

rearranging the Michelas-Menten equation to make the substrate the subject.

\n

rebelmaths

", "licence": "Creative Commons Attribution 4.0 International"}, "advice": "

start by multiplying both sides by the denominator

\n

for example if you have $V=\\frac{5S}{S+12}$ then multiply both sides by $(S+12)$

\n

this gives:  $V(S+12)=\\frac{5S}{S+12} (S+12) $

\n

the (S+12) term on the right hand side cancels out to give: $V(S+12)=5S$

\n

now expand out the brackets:  $VS+12V=5S$

\n

then collect the like terms, you want to get all the terms with S in them onto one side, so subtract VS from both sides:

\n

$VS-VS+12V=5S-VS$

\n

this becomes $12V=5S-VS$

\n

now you can factorise the right hand side: $12V=S(5-V)$

\n

then divide both sides by (5-V) to leave S on its own: $\\frac{12V}{5-V}=S$

\n

", "extensions": [], "rulesets": {}, "variable_groups": [], "type": "question", "tags": ["algebra", "biology", "rearranging equations", "Rebel", "REBEL", "rebel", "rebelmaths", "transpose"], "variablesTest": {"maxRuns": 100, "condition": ""}, "statement": "", "contributors": [{"name": "Julie Crowley", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/113/"}, {"name": "Simon Thomas", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/3148/"}]}]}], "contributors": [{"name": "Julie Crowley", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/113/"}, {"name": "Simon Thomas", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/3148/"}]}