// Numbas version: exam_results_page_options {"name": "Indefinite Integrals Q4 2019 (custom feedback)", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"advice": "

Indefinite Integrals

", "statement": "

Solve the following indefinite integrals, using $C$ to represent an unknown constant.

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$\\int (\\frac{2}{x^4}+\\frac{3}{x}+1)\\mathrm{dx}$

", "variableReplacementStrategy": "originalfirst", "showPreview": true, "scripts": {}, "expectedVariableNames": [], "type": "jme", "marks": 1, "checkingType": "absdiff", "variableReplacements": [], "checkVariableNames": false, "customMarkingAlgorithm": "malrules:\n [\n [\"-2/3*1/x^3+3ln(x)+x\",\"Don't forget the constant of integration!\"], \n [\"-2x^(-5)/5+3ln(x)+x+C\", \"Check the first term again. It looks like you have subtracted 1 from the power.\"],\n [\"-2x^(-5)/5+3ln(x)+x\", \"Check the first term again. It looks like you have subtracted 1 from the power.\"],\n [\"-2x^(-5)/5+ln(3x)+x+C\", \"The first two terms are incorrect. First term: It looks like you have subtracted 1 from the power. 2nd term: $\\\\frac{3}{x}=3\\\\left(\\\\frac{1}{x}\\\\right)$. What do you get when you integrate $\\\\frac{1}{x}$?\"],\n [\"-2x^(-5)/5+ln(3x)+x\", \"The first two terms are incorrect. First term: It looks like you have subtracted 1 from the power. 2nd term: $\\\\frac{3}{x}=3\\\\left(\\\\frac{1}{x}\\\\right)$. What do you get when you integrate $\\\\frac{1}{x}$?\"],\n [\"-2/(3x^3)+ln(3x)+x+C\", \"Check the second term: $\\\\frac{3}{x}=3\\\\left(\\\\frac{1}{x}\\\\right)$. What do you get when you integrate $\\\\frac{1}{x}$?\"],\n [\"-2/(3x^3)+ln(3x)+x\", \"Check the second term: $\\\\frac{3}{x}=3\\\\left(\\\\frac{1}{x}\\\\right)$. What do you get when you integrate $\\\\frac{1}{x}$?\"],\n [\"-2/(3x^3)+3+x+C\", \"Check the second term: $\\\\frac{3}{x}=3x^{-1}$. The power rule doesn't work if the power on the $x$ is $-1$, because we would end up getting $\\\\frac{x^0}{0}$ and dividing by zero is not defined.\"],\n [\"-2/(3x^3)+3+x\", \"Check the second term: $\\\\frac{3}{x}=3x^{-1}$. The power rule doesn't work if the power on the $x$ is $-1$, because we would end up getting $\\\\frac{x^0}{0}$ and dividing by zero is not defined.\"],\n [\"-2x^(-5)/5+3+x+C\", \"The first two terms are incorrect. First term: It looks like you have subtracted 1 from the power. 2nd term: $\\\\frac{3}{x}=3x^{-1}$. The power rule doesn't work if the power on the $x$ is $-1$, because we would end up getting $\\\\frac{x^0}{0}$ and dividing by zero is not defined.\"],\n [\"-2x^(-5)/5+3+x\", \"The first two terms are incorrect. First term: It looks like you have subtracted 1 from the power. 2nd term: $\\\\frac{3}{x}=3x^{-1}$. The power rule doesn't work if the power on the $x$ is $-1$, because we would end up getting $\\\\frac{x^0}{0}$ and dividing by zero is not defined.\"],\n [\"2ln(x^4)+3ln(x)+x\",\"Check the first term again. You can only use the $\\\\ln$ rule if the power on the variable below the line is 1.\"],\n [\"2ln(x^4)+3ln(x)+x+C\",\"Check the first term again. You can only use the $\\\\ln$ rule if the power on the variable below the line is 1.\"]\n ]\n\n\nparsed_malrules: \n map(\n [\"expr\":parse(x[0]),\"feedback\":x[1]],\n x,\n malrules\n )\n\nagree_malrules (Do the student's answer and the expected answer agree on each of the sets of variable values?):\n map(\n len(filter(not x ,x,map(\n try(\n resultsEqual(unset(question_definitions,eval(studentexpr,vars)),unset(question_definitions,eval(malrule[\"expr\"],vars)),settings[\"checkingType\"],settings[\"checkingAccuracy\"]),\n message,\n false\n ),\n vars,\n vset\n )))Simple Indefinite Integrals

\n

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