// Numbas version: exam_results_page_options
{"name": "Indefinite Integrals Q7 2019 (custom feedback)", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"metadata": {"description": "<p>Simple Indefinite Integrals</p>\n<p></p>", "licence": "Creative Commons Attribution 4.0 International"}, "extensions": [], "ungrouped_variables": ["a", "c", "b", "d", "f"], "preamble": {"css": "", "js": ""}, "rulesets": {}, "parts": [{"variableReplacementStrategy": "originalfirst", "customMarkingAlgorithm": "malrules:\n  [\n    [\"3/4p-p^2-4/p\",\"Don't forget the integration constant!\"],\n    [\"3/4p-p^2+4ln(p^2)+C\", \"Check the third term again. $\\\\int \\\\frac{1}{p} \\\\ dp = \\\\ln p$ but $\\\\int \\\\frac{1}{p^n} \\\\ dp$ for $n \\\\neq 1$ is not $\\\\ln(p^n)$. That is, if the power on $p$ under the line is anything other than $1$, the integral is not $\\\\ln$.\"],\n    [\"3/4p-p^2+4ln(p^2)\", \"Check the third term again. $\\\\int \\\\frac{1}{p} \\\\ dp = \\\\ln p$ but $\\\\int \\\\frac{1}{p^n} \\\\ dp$ for $n \\\\neq 1$ is not $\\\\ln(p^n)$. That is, if the power on $p$ under the line is anything other than $1$, the integral is not $\\\\ln$.\"],\n    [\"-p^2-4/p+C\",\"It looks like you have differentiated the first term rather than integrating.\"],\n    [\"-p^2-4/p\",\"It looks like you have differentiated the first term rather than integrating.\"],\n    [\"-p^2+4ln(p^2)+C\",\"There are two errors here. Firstly, it looks like you have differentiated the first term rather than integrating. Secondly, $\\\\int \\\\frac{1}{p} \\\\ dp = \\\\ln p$ but $\\\\int \\\\frac{1}{p^n} \\\\ dp$ for $n \\\\neq 1$ is not $\\\\ln(p^n)$. That is, if the power on $p$ under the line is anything other than $1$, the integral is not $\\\\ln$.\"],\n    [\"-p^2+4ln(p^2)\",\"There are two errors here. Firstly, it looks like you have differentiated the first term rather than integrating. Secondly, $\\\\int \\\\frac{1}{p} \\\\ dp = \\\\ln p$ but $\\\\int \\\\frac{1}{p^n} \\\\ dp$ for $n \\\\neq 1$ is not $\\\\ln(p^n)$. That is, if the power on $p$ under the line is anything other than $1$, the integral is not $\\\\ln$.\"]\n     ]\n\n\nparsed_malrules: \n    map(\n        [\"expr\":parse(x[0]),\"feedback\":x[1]],\n        x,\n        malrules\n    )\n\nagree_malrules (Do the student's answer and the expected answer agree on each of the sets of variable values?):\n    map(\n        len(filter(not x ,x,map(\n            try(\n                resultsEqual(unset(question_definitions,eval(studentexpr,vars)),unset(question_definitions,eval(malrule[\"expr\"],vars)),settings[\"checkingType\"],settings[\"checkingAccuracy\"]),\n                message,\n                false\n            ),\n            vars,\n            vset\n        )))<settings[\"failureRate\"],\n        malrule,\n        parsed_malrules\n    )\n\nmatched_malrules:\n  filter(x[0],x,zip(agree_malrules,parsed_malrules))\n  \nmalrule_feedback:\n    assert(numericallyCorrect,\n        assert(len(matched_malrules)=0,\n            set_credit(0,matched_malrules[0][1][\"feedback\"])\n        )\n    )\n\nmark:\n    apply(studentExpr);\n    apply(unexpectedVariables);\n    apply(numericallyCorrect);\n    apply(malrule_feedback);\n    apply(failMinLength);\n    apply(failMaxLength);\n    apply(forbiddenStringsPenalty);\n    apply(requiredStringsPenalty) ", "failureRate": 1, "checkVariableNames": false, "variableReplacements": [], "scripts": {}, "expectedVariableNames": [], "vsetRangePoints": 5, "marks": 1, "unitTests": [], "checkingAccuracy": 0.001, "checkingType": "absdiff", "showPreview": true, "answer": "3/4p-p^2-4/p+c", "showFeedbackIcon": true, "extendBaseMarkingAlgorithm": true, "vsetRange": [0, 1], "showCorrectAnswer": true, "type": "jme", "prompt": "<p>$\\int{(\\frac{3}{4}-2p+\\frac{4}{p^2}})\\mathrm{dp}$</p>"}], "variablesTest": {"maxRuns": 100, "condition": ""}, "advice": "<p>Indefinite Integrals</p>", "name": "Indefinite Integrals Q7 2019 (custom feedback)", "variable_groups": [], "tags": [], "functions": {}, "statement": "<p>Solve the following indefinite integrals, using $C$ to represent an unknown constant.</p>", "variables": {"f": {"templateType": "anything", "description": "", "group": "Ungrouped variables", "definition": "random(1..8 except d)", "name": "f"}, "b": {"templateType": "anything", "description": "", "group": "Ungrouped variables", "definition": "random(2..9 except a)", "name": "b"}, "c": {"templateType": "anything", "description": "", "group": "Ungrouped variables", "definition": "random(1..9 except a except b)", "name": "c"}, "a": {"templateType": "anything", "description": "", "group": "Ungrouped variables", "definition": "random(2..9)", "name": "a"}, "d": {"templateType": "anything", "description": "", "group": "Ungrouped variables", "definition": "random(1..8)", "name": "d"}}, "type": "question", "contributors": [{"name": "Clodagh Carroll", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/384/"}, {"name": "Violeta CIT", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/1030/"}]}]}], "contributors": [{"name": "Clodagh Carroll", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/384/"}, {"name": "Violeta CIT", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/1030/"}]}