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Six adults spent {x1}, {x2}, {x3}, {x4}, {x5} and {x6} euros on lottery tickets last month. Let $y$ denote last month's lottery ticket expenses for an adult.
", "advice": "The symbol $\\Sigma$ means 'sum of' or 'total'.
\n(a)
\n$\\sum y $ means add up the $y$ values.
\n$\\var{x1}+\\var{x2}+\\var{x3}+\\var{x4}+\\var{x5}+\\var{x6}=\\var{x1+x2+x3+x4+x5+x6}$
\n(b)
\n$(\\sum y)^2 $ means add up the $y$ values and then square your answer.
\n Using your answer in part (a), $\\var{x1+x2+x3+x4+x5+x6}^2=\\var{(x1+x2+x3+x4+x5+x6)^2}$
(c)
\n$\\sum y^2 $ means square each of the $y$ values then add them up.
\n$\\var{x1}^2+\\var{x2}^2+\\var{x3}^2+\\var{x4}^2+\\var{x5}^2+\\var{x6}^2=\\var{x1^2}+\\var{x2^2}+\\var{x3^2}+\\var{x4^2}+\\var{x5^2}+\\var{x6^2}=\\var{x1^2+x2^2+x3^2+x4^2+x5^2+x6^2}$
\nNote this does not give the same answer as the calculation in (b)!
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\nrebelmaths
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\n(a)
\n$\\sum y = $ [[0]]
\n(b)
\n$(\\sum y)^2 = $ [[1]]
\n(c)
\n$\\sum y^2 = $ [[2]]
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