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Given vectors $\\boldsymbol{a,\\;b}$, find $\\boldsymbol{a\\times b}$

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rebelmaths

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Given the vectors:
\\[\\boldsymbol{a}=\\simplify[std]{{a}v:i+{b}v:j+{g}v:k},\\;\\;\\;\\boldsymbol{b}=\\simplify[std]{{c}v:i+{d}v:j+{f}v:k}\\]

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answer the following question:

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Find $\\boldsymbol{a\\times b} =\\;\\;$ [[0]]$\\boldsymbol{i}$+[[1]]$\\boldsymbol{j}$+[[2]]$\\boldsymbol{k}$

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To find $\\boldsymbol{a\\times b}$ we take the determinant of the 3 by 3 matrix with first row = $(\\boldsymbol{i,j,k})$, second row = $\\boldsymbol{a}$ and third row = $\\boldsymbol{b}$

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Hence:

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\\[ \\begin{eqnarray*} \\boldsymbol{a\\times b}&=& \\begin{vmatrix} \\boldsymbol{i} & \\boldsymbol{j} &\\boldsymbol{k}\\\\ \\var{a} & \\var{b} & \\var{g}\\\\ \\var{c} & \\var{d} & \\var{f} \\end{vmatrix}\\\\ \\\\&=& \\begin{vmatrix} \\var{b} & \\var{g} \\\\ \\var{d} & \\var{f} \\end{vmatrix}\\boldsymbol{i}-\\begin{vmatrix} \\var{a} & \\var{g} \\\\ \\var{c} & \\var{f} \\end{vmatrix}\\boldsymbol{j}+\\begin{vmatrix} \\var{a} & \\var{b} \\\\ \\var{c} & \\var{d} \\end{vmatrix}\\boldsymbol{k} \\\\ \\\\ &=&\\simplify[]{({b}*{f}-{g}*{d})v:i - ({a}*{f} - {g}*{c})v:j+({a}*{d}-{b}*{c})v:k}\\\\ \\\\ &=&\\simplify[std]{{b*f-g*d}v:i+{g*c-a*f}v:j+{a*d-b*c}v:k} \\end{eqnarray*} \\]

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