// Numbas version: finer_feedback_settings {"name": "Quiz copy of Find determinants and inverses of 2x2 matrices", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"rulesets": {"std": ["all", "fractionNumbers", "!collectNumbers"]}, "functions": {"inverse": {"parameters": [["m", "matrix"]], "type": "matrix", "definition": "matrix([\n [m[1][1], -m[0][1]],\n [-m[1][0], m[0][0]]\n])/det(m)", "language": "jme"}}, "advice": "
The determinant of a matrix $\\mathrm{M} = \\begin{pmatrix} a&b \\\\ c&d \\end{pmatrix}$ is given by
\n\\[ \\det\\left(\\mathrm{M}\\right) = ad-bc \\]
\nIf we have two $n \\times n$ matrices $M$ and $N$, then
\n\\[ \\det\\left(\\mathrm{MN}\\right) = \\det\\left(\\mathrm{M}\\right)\\det\\left(\\mathrm{N}\\right) \\]
\nAnd it follows that if we have a third matrix $P$,
\n\\[ \\det\\left(\\mathrm{MNP}\\right) = \\det\\left(\\mathrm{M}\\right)\\det\\left(\\mathrm{N}\\right)\\det\\left(\\mathrm{P}\\right) \\]
\nThus for our example we have:
\n\\begin{align}
\\det\\left(\\mathrm{A}\\right) &= \\simplify[]{{a11}*{a22}-{a12}*{a21} = {det(a)}} \\\\
\\det\\left(\\mathrm{B}\\right) &= \\simplify[]{{b11}*{b22}-{b12}*{b21} = {det(b)}} \\\\
\\det\\left(\\mathrm{C}\\right) &= \\simplify[]{{c11}*{c22}-{c12}*{c21} = {det(c)}}
\\end{align}
\\begin{align}
\\det\\left( \\mathrm{ABC} \\right) &= \\det(\\mathrm{A}) \\det(\\mathrm{B}) \\det(\\mathrm{C}) \\\\
&= \\simplify[]{{det(a)}*{det(b)}*{det(c)}} \\\\
&= \\var{det(a*b*c)}
\\end{align}
Suppose $\\mathrm{M} = \\begin{pmatrix} a&b \\\\ c&d \\end{pmatrix}$ is a $2 \\times 2$ matrix and $\\det\\left(\\mathrm{M}\\right) = \\Delta \\neq 0$.
\nThen $\\mathrm{M}$ is invertible and
\n\\[ \\mathrm{M}^{-1} = \\frac{1}{\\Delta} \\begin{pmatrix} d & -b\\\\ -c& a \\end{pmatrix}=\\begin{pmatrix} \\frac{d}{\\Delta} & -\\frac{b}{\\Delta}\\\\ -\\frac{c}{\\Delta}& \\frac{a}{\\Delta} \\end{pmatrix}\\]
\nApplying this to these examples we obtain:
\n\\[ \\simplify[fractionnumbers]{matrix:A^(-1)={inverse(a)}} \\]
\n\\[ \\simplify[fractionnumbers]{matrix:B^(-1)={inverse(b)}} \\]
\n\\[ \\simplify[fractionnumbers]{matrix:C^(-1)={inverse(c)}} \\]
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\n\\begin{align} \\mathbf{A} &= \\var{a}, & \\mathbf{B} &= \\var{b}, & \\mathbf{C} &= \\var{c} \\end{align}
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\n$\\mathrm{det}\\left(A\\right) = $ [[0]]
\n$\\mathrm{det}\\left(B\\right) = $ [[1]]
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\n$\\mathbf{A}^{-1} = $ [[0]]
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