// Numbas version: exam_results_page_options {"name": "Simon's copy of Q3 Solve for x and y on a given triangle", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"variables": {"lent11": {"definition": "random(20..28#5)", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "lent11"}, "ans32": {"definition": "(lent31/(sin(radians(ang31))))*sin(radians(180-(ang32+ang31)))", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "ans32"}, "lent22": {"definition": "random(35..48)", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "lent22"}, "ang31": {"definition": "random(71..85)", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "ang31"}, "ans12": {"definition": "90-(degrees(arcsin(lent11/(lent12/(sin(radians(90)))))))", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "ans12"}, "lent12": {"definition": "random(41..51#2)", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "lent12"}, "lent31": {"definition": "random(72..98#2)", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "lent31"}, "ans33": {"definition": "0.5*lent31*h3", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "ans33"}, "ang32": {"definition": "random(47..55)", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "ang32"}, "ans22": {"definition": "(lent21/(sin(radians(90))))*sin(radians(90-(ans21)))", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "ans22"}, "lent21": {"definition": "random(55..75)", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "lent21"}, "h3": {"definition": "(ans32/(sin(radians(90))))*sin(radians(ang32))", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "h3"}, "ans21": {"definition": "degrees(arcsin(lent22/(lent21/(sin(radians(90))))))", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "ans21"}, "ans31": {"definition": "(lent31/(sin(radians(ang31))))*sin(radians(ang32))", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "ans31"}, "ans11": {"definition": "sqrt(lent12^2 - lent11^2)", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "ans11"}, "l2": {"definition": "(ans32/(sin(radians(90))))*sin(radians(180-(ang32+90)))", "group": "Ungrouped variables", "description": "", "templateType": "anything", "name": "l2"}}, "parts": [{"prompt": "

Find the values of x and y:

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Note:The bottom left angle is a right angle (90$^{\\circ}$).

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{tri2(lent21,lent22,ans22)}

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$x$ = [[0]]mm

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$Y$ = [[1]] $^{\\circ}$

", "showFeedbackIcon": true, "steps": [{"prompt": "

To find x: Use Pythagoras' Theorem to find the missing side.

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To find y: For the most accurate answer use the sides that were given. What trigonometric ratio includes those two sides? - sin.

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Remember to use the inverse $\\sin^{-1}$ to find the angle.

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Find the values of x and y:

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Note:The top right angle is a right angle (90$^{\\circ}$).

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{tri(lent11,lent12,ans12)}

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$X$ = [[0]] $^{\\circ}$

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$y$ = [[1]] mm

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Use Pythagoras' Theorem and trigonometry to solve the following questions to 2 decimal places. 

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Note: You may need to scroll down to see the diagrams.

", "advice": "

(a)

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To find $x$ we can use Pythagoras' Theorem:

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$x^2+\\var{lent22}^2=\\var{lent21}^2$

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$x^2=\\var{lent21}^2-\\var{lent22}^2$

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$x=\\sqrt{\\var{lent21}^2-\\var{lent22}^2}=\\var{precround({ans22},2)}$ mm

\n

\n

To find $y$ we can use trigonometry as follows:

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$\\sin(Y) = \\frac{\\var{lent22}}{\\var{lent21}}$

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Therefore:

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$Y = \\sin^{-1}(\\frac{\\var{lent22}}{\\var{lent21}})=\\var{precround({ans21},2)}$

\n

\n

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(b)

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To find $X$ we can use trigonometry as follows:

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$\\cos(X) = \\frac{\\var{lent11}}{\\var{lent12}}$

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Therefore:

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$X = \\cos^{-1}(\\frac{\\var{lent11}}{\\var{lent12}})=\\var{precround({ans12},2)}$

\n

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To find $y$ we can use Pythagoras' Theorem:

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$y^2+\\var{lent11}^2=\\var{lent12}^2$

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$y^2=\\var{lent12}^2-\\var{lent11}^2$

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$y=\\sqrt{\\var{lent12}^2-\\var{lent11}^2}=\\var{precround({ans11},2)}$ mm

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Find angle and side in a right angled triangle.

\n

rebelmaths

", "licence": "Creative Commons Attribution 4.0 International"}, "variablesTest": {"condition": "", "maxRuns": 100}, "type": "question", "contributors": [{"name": "TEAME CIT", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/591/"}, {"name": "Simon Thomas", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/3148/"}]}]}], "contributors": [{"name": "TEAME CIT", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/591/"}, {"name": "Simon Thomas", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/3148/"}]}