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Er is hier geen gemeenschappelijke factor.

Gebruik de formule $(a+b)(a-b)=a^2-b^2$. 

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Er is een gemeenschappelijke factor die je eerst moet voorop zetten:  $\\var{gg}$ 

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Gebruik $a^2-b^2 = (a+b)(a-b)$ voor het deel dat overblijft

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$\\simplify{{aa}x^2-{bb}}$ = [[0]].

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Ensure you factorise the expression.

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Ensure you factorise the expression.

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We should recognise this as a difference of two squares, where $\\simplify{{c[0]}^2/{c[2]}^2 x^2}$ is $\\left(\\simplify{{c[0]}/{c[2]}x}\\right)^2$ and $\\simplify{{c[1]}^2/{c[3]}^2}$ is $\\left(\\simplify{{c[1]}/{c[3]}}\\right)^2$. Therefore

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$\\simplify{{c[0]}^2/{c[2]}^2 x^2-{c[1]}^2/{c[3]}^2}=\\simplify{({c[0]}/{c[2]}x+{c[1]}/{c[3]})({c[0]}/{c[2]}x-{c[1]}/{c[3]})}.$

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$\\simplify{{c[0]}^2/{c[2]}^2 x^2-{c[1]}^2/{c[3]}^2}$ = [[0]].

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Ensure you factorise the expression.

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Ensure you factorise the expression.

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Gebruik de formule om het verschil van twee kwadraten te ontbinden. 

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