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Gebruik de formule voor het ontbinden van een merkwaardige drieterm of zet eerst een gemeenschappelijke factor voorop en gebruik daarna die formule. 

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Ensure you factorise the expression.

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Ensure you factorise the expression.

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Gebruik de formule $a^2+2ab+b^2=(a+b)^2$. 

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$\\var{aa}x^2=(\\var{a}x)^2$, 

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$\\var{bb}=\\simplify{({b})^2}$ and

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$\\var{mid}x=2(\\var{a}x)(\\var{b})$.

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Er is een gemeenschappelijke factor $\\var{g^2}$, dus plaatsen we die eerst voorop. 

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Gebruik daarna de formule $\\simplify{ a^2+2ab+b^2=(a+b)^2}$ op de de veelterm die overblijft. 

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$\\simplify{{aa}x^2+{mid}x+{bb}}$ = [[0]].

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Ensure you factorise the expression.

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Ensure you factorise the expression.

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Recall that $(a+b)^2=(a+b)(a+b)=a^2+2ab+b^2$ is called a perfect square.

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In fact, $\\simplify{{c[0]^2}/{c[1]^2} x^2+{2c[0]*d}/{(c[1]*c[2])}x+{d^2}/{c[2]^2}}$ is also a perfect square, since

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That is, 

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$\\simplify{{c[0]^2}/{c[1]^2} x^2+{2c[0]*d}/{(c[1]*c[2])}x+{d^2}/{c[2]^2}}=\\simplify{({c[0]}/{c[1]}x+{d}/{c[2]})^2}$.

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You can always check your factorisation by expanding.

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$\\simplify{{c[0]^2}/{c[1]^2} x^2+{2c[0]*d}/{(c[1]*c[2])}x+{d^2}/{c[2]^2}}$ = [[0]].

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