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Rearranging equations to change the subject

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$\\simplify{y={c[0]}x+{c[1]}}$

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$x=$ [[0]]

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$\\simplify{y={c[2]}x/({c[3]}+x)}$

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$x=$ [[0]]

\n

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$\\simplify{y={c[7]}-{c[8]}/({c[9]}+x)}$

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$x=$ [[0]]

\n

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$\\simplify{y=sqrt(x+{c[10]})}$

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$x=$ [[0]]

\n

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$\\simplify{y=1/x+{c[11]}}$

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$x=$ [[0]]

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Rearrange these equations to make $x$ the subject.

", "preamble": {"js": "", "css": ""}, "name": "Maria's copy of Simon's copy of Inverse Functions", "rulesets": {}, "variables": {"c": {"definition": "repeat(random(-5..5 except 0 except 1 except -1),15)", "description": "", "group": "Ungrouped variables", "name": "c", "templateType": "anything"}}, "advice": "

(a)

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$\\simplify{y={c[0]}x+{c[1]}}$

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$\\simplify{y-{c[1]}={c[0]}x}$

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$\\simplify{(y-{c[1]})/{c[0]}={x}}$          (dividing both sides by $\\var{c[0]}$)

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(b)

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$\\simplify{y={c[2]}x/({c[3]}+x)}$

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$\\simplify{y*({c[3]}+x)={c[2]}}x$        (multiply both sides by denominator)

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$\\simplify{y*{c[3]}+x y={c[2]}}x$        (expanding bracket)

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$\\simplify{y*{c[3]}={c[2]}x- y x}$        (moving all $x$ to the same side)

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$\\simplify{y*{c[3]}=x({c[2]}- y)}$        (factorising)

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$\\simplify{(y*{c[3]})/({c[2]}- y)=x}$

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(c)

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$\\simplify{y={c[7]}-{c[8]}/({c[9]}+x)}$

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$\\simplify{y-{c[7]}=-{c[8]}/({c[9]}+x)}$

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$\\simplify{({c[9]}+x)=-{c[8]}/(y-{c[7]})}$

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$\\simplify{x=-{c[9]}-{c[8]}/(y-{c[7]})}$                which is algebraically the same as  $\\simplify{x=(-{c[9]}(y-{c[7]})-{c[8]})/(y-{c[7]})}=\\simplify{(-{c[9]}y+{c[7]*c[9]-c[8]})/(y-{c[7]})}$

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(d)

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$\\simplify{y=sqrt(x+{c[10]})}$

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$\\simplify{y^2=(x+{c[10]})}$          (squaring both sides)

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$\\simplify{y^2-{c[10]}=x}$   

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(e)

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$\\simplify{y=1/x+{c[11]}}$

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$\\simplify{y-{c[11]}=1/x}$

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$\\simplify{x(y-{c[11]})=1}$           (multiply both sides by $x$)

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$\\simplify{x=1/(y-{c[11]})}$

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