// Numbas version: exam_results_page_options {"name": "Simon's copy of Perform z-test for hypothesis given sample mean and population variance", "extensions": ["stats"], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"extensions": ["stats"], "rulesets": {}, "metadata": {"licence": "Creative Commons Attribution 4.0 International", "description": "
Provided with information on a sample with sample mean and known population variance, use the z test to either accept or reject a given null hypothesis.
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\n$\\operatorname{H}_0\\;: \\; \\mu=\\;$[[0]]
\nStep 2: Alternative Hypothesis
\n$\\operatorname{H}_1\\;: \\; \\mu \\lt\\;$[[1]]
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\nShould we use the z or t test statistic? [[0]] (enter z or t).
\nNow calculate the test statistic = [[1]]
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\nUse tables to find a range for your $p$-value.
\nChoose the correct range here for $p$ : [[0]]
\n \n ", "gaps": [{"type": "1_n_2", "marks": 0, "minMarks": 0, "shuffleChoices": false, "scripts": {}, "customName": "", "variableReplacements": [], "showCellAnswerState": true, "unitTests": [], "customMarkingAlgorithm": "", "maxMarks": 0, "showFeedbackIcon": true, "useCustomName": false, "displayType": "radiogroup", "showCorrectAnswer": true, "matrix": "mm", "displayColumns": 0, "extendBaseMarkingAlgorithm": true, "variableReplacementStrategy": "originalfirst", "choices": ["{pm[0]}", "{pm[1]}", "{pm[2]}", "{pm[3]}"]}], "scripts": {}, "customName": "", "variableReplacements": [], "unitTests": [], "customMarkingAlgorithm": "", "showFeedbackIcon": true, "useCustomName": false, "sortAnswers": false, "showCorrectAnswer": true, "extendBaseMarkingAlgorithm": true, "variableReplacementStrategy": "originalfirst"}, {"type": "gapfill", "marks": 0, "prompt": "\nStep 5: Conclusion
\n\n
Given the $p$ - value and the range you have found, what is the strength of evidence against the null hypothesis?
\n[[0]]
\nYour Decision:
\n[[1]]
\n\n
Conclusion:
\n[[2]]
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\n{claim}$\\var{thismuch}${units} and {var} {thisvar}.
\n{test}
\nTo investigate a sample of $\\var{n}$ {things} {resultis} $\\var{m}${units}.
\nPerform an appropriate hypothesis test to see if the claim made by the customers is substantiated.
\n ", "ungrouped_variables": ["claim", "var", "pval", "evi1", "crit", "zval1", "things", "tol", "units", "thismuch", "pm", "correctc", "resultis", "thisvar", "test", "zval", "fac", "confl", "evi", "mm", "dothis", "m", "dmm", "n", "this", "stand"], "advice": "(a)
\nStep 1: Null Hypothesis
\n$\\operatorname{H}_0\\;: \\; \\mu=\\;\\var{thismuch}$
\nStep 2: Alternative Hypothesis
\n$\\operatorname{H}_1\\;: \\; \\mu \\lt\\;\\var{thismuch}$
\n\n(b)
\nWe should use the z statistic as the population variance is known.
\nThe test statistic:
\n\\[z =\\frac{ \\var{m} -\\var{thismuch}} {\\sqrt{\\frac{\\var{thisvar}}{\\var{n}}}} = \\var{dpformat(zval1,3)}\\]
\nto 3 decimal places.
\n\n(c)
\nSince we are carrying out a 1-tailed hypothesis test (we are testing specifically for under-filling) we must use the 1-tailed critical values for the normal distribution.
\n{table([['Critical Value',-crit[0],-crit[1],-crit[2]]],['p value','10%','5%','1%'])}
\nWe see that the $p$ value {pm[pval]}.
\n
(d)
Hence there is {evi1[pval]} evidence against $\\operatorname{H}_0$ and so we {dothis} $\\operatorname{H}_0$.
\n{Correctc}
", "preamble": {"css": "", "js": ""}, "type": "question", "contributors": [{"name": "Newcastle University Mathematics and Statistics", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/697/"}, {"name": "Simon Thomas", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/3148/"}]}]}], "contributors": [{"name": "Newcastle University Mathematics and Statistics", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/697/"}, {"name": "Simon Thomas", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/3148/"}]}