// Numbas version: finer_feedback_settings
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"description": "", "definition": "random(-9..9 except 0)", "name": "f"}}, "preamble": {"js": "", "css": ""}, "name": "Simon's copy of Represent a linear map as a matrix with a given basis", "statement": "<p>Let $P_n$ denote the vector space over the reals of polynomials $p(x)$ of degree $n$ &nbsp;with coefficients in the real numbers.</p>\n<p>Let the linear map \\[\\phi: P_4 \\rightarrow P_4 \\] be defined by:</p>\n<p>\\[\\phi(p(x)) = \\simplify[all,!collectnumbers]{{a} * p(x) + ({b} * x + {c}) * p'(x) + (x ^ 2 + {d} * x + {f}) * p''(x)}\\]</p>\n<p>where &nbsp;$p'(x)$ is the first derivative of $p(x)$ &nbsp;and $p''(x)$ the second derivative.&nbsp;</p>", "extensions": [], "functions": {}, "metadata": {"description": "<p>Let $P_n$ denote the vector space over the reals of polynomials $p(x)$ of degree $n$ &nbsp;with coefficients in the real numbers.</p>\n                <p>Let the linear map $\\phi: P_4 \\rightarrow P_4$ be defined by:</p>\n                <p>$\\phi(p(x))=ap(x) + (bx + c)p'(x) + (x ^ 2 + dx + f)p''(x)$</p>\n                <p>Using the standard basis for range and domain find the matrix given by $\\phi$.</p>", "licence": "Creative Commons Attribution 4.0 International"}, "rulesets": {}, "variablesTest": {"maxRuns": 100, "condition": ""}, "parts": [{"gaps": [{"correctAnswerStyle": "plain", "minValue": "{a}", "scripts": {}, "showCorrectAnswer": true, "useCustomName": false, "customMarkingAlgorithm": "", "mustBeReduced": false, "type": "numberentry", "notationStyles": ["plain", "en", "si-en"], "allowFractions": false, "maxValue": "{a}", "extendBaseMarkingAlgorithm": true, "variableReplacementStrategy": "originalfirst", "correctAnswerFraction": false, "variableReplacements": [], "showFeedbackIcon": true, "mustBeReducedPC": 0, "showFractionHint": true, "marks": 0.5, "customName": "", "unitTests": []}, {"correctAnswerStyle": "plain", "minValue": "{c}", "scripts": {}, "showCorrectAnswer": true, "useCustomName": false, "customMarkingAlgorithm": "", 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"tags": [], "advice": "<p>We have:</p>\n<p>\\[\\phi(1) =\\simplify[]{ {a} * 1 + ({b} * x + {c}) * 0 + (x ^ 2 + {d} * x + {f}) * 0 = {a} = {a} * 1 + 0 * x + 0 * x ^ 2 + 0 * x ^ 3 + 0 * x ^ 4}\\]</p>\n<p>which gives the first column of the matrix.</p>\n<p></p>\n<p>\\[\\phi(x) = \\simplify[]{{a} * x + ({b} * x + {c}) * 1 + (x ^ 2 + {d} * x + {f}) * 0 = {c} + {a + b} * x = {c} * 1 + {a + b} * x + 0 * x ^ 2 + 0 * x ^ 3 + 0 * x ^ 4}\\]</p>\n<p>gives the second column of the matrix.</p>\n<p></p>\n<p>\\[\\phi(x ^ 2) = \\simplify[]{{a} * x ^ 2 + ({b} * x + {c}) * 2 * x + (x ^ 2 + {d} * x + {f}) * 2 = {2 * f} + {2 * d + 2 * c} * x + {a + 2 * b + 2} * x ^ 2 = {2 * f} * 1 + {2 * d + 2 * c} * x + {a + 2 * b + 2} * x ^ 2 + 0 * x ^ 3 + 0 * x ^ 4}\\]</p>\n<p>gives the third column of the matrix.</p>\n<p></p>\n<p>Continuing on in this way for $\\phi(x^3),\\;\\phi(x^4)$ we obtain the matrix for $\\phi$ with respect to the given bases for domain and range.</p>\n<p>\\[\\begin{pmatrix}\\var{a}&amp;\\var{c}&amp;\\var{2*f}&amp;0&amp;0\\\\0&amp;\\var{a+b}&amp;\\var{2*d+2*c}&amp;\\var{6*f}&amp;0\\\\0&amp;0&amp;\\var{a+2*b+2}&amp;\\var{3*c+6*d}&amp;\\var{12*f}\\\\0&amp;0&amp;0&amp;\\var{a+3*b+6}&amp;\\var{4*c+12*d}\\\\0&amp;0&amp;0&amp;0&amp;\\var{a+4*b+12}\\end{pmatrix}\\]</p>", "type": "question", "contributors": [{"name": "Newcastle University Mathematics and Statistics", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/697/"}, {"name": "Simon Thomas", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/3148/"}]}]}], "contributors": [{"name": "Newcastle University Mathematics and Statistics", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/697/"}, {"name": "Simon Thomas", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/3148/"}]}