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$\\sqrt{\\var{a4}-\\var{a3}}=$[[0]]

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$\\sqrt{\\var{b4}+\\var{b3}}=$[[0]]

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$\\sqrt{\\var{c4}-\\var{c3}}=$[[0]]

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$\\sqrt[4]{\\var{d4}-\\var{d3}}=$[[0]]

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$\\sqrt[3]{\\var{e3}+\\var{e3}}=$[[0]]

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$\\sqrt[3]{(-\\var{e3}-\\var{e3})}=$[[0]]

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Indices and Roots

Questions based on Exercise Intro(b) from the Textbook \"Engineering Maths through Applications\" by Kuldeep Singh.

Intended for use as Homework Exercises.

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Using your calculator or otherwise, calculate:

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b1

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For these questions, we first need to carry out the arithmetic then take the root of the result:

\n

a)   $\\sqrt{\\var{a4}-\\var{a3}}=\\sqrt{\\var{a2}}=\\var{a1}$

\n

b)   $\\sqrt{\\var{b4}+\\var{b3}}=\\sqrt{\\var{b2}}=\\var{b1}$

\n

c)   $\\sqrt{\\var{c4}-\\var{c3}}=\\sqrt{\\var{c2}}=\\var{c1}$

\n

d)   $\\sqrt[4]{\\var{d4}-\\var{d3}}=\\sqrt[4]{\\var{d2}}=\\var{d1}$

\n

e)   $\\sqrt[3]{\\var{e3}+\\var{e3}}=\\sqrt[3]{\\var{e2}}=\\var{e1}$

\n

f)   $\\sqrt[3]{(-\\var{e3}-\\var{e3})}=\\sqrt[3]{-\\var{e2}}=-\\var{e1}$

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