// Numbas version: finer_feedback_settings
{"name": "cash flow amount  - ordinary perpetuity", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"variable_groups": [], "functions": {}, "statement": "<p>If you are unsure of how to do&nbsp;a question, click on&nbsp;<em>Reveal answers</em>&nbsp;to see the full working. Then, once you understand how to do the question, click on&nbsp;<em>Try another question like this one</em>&nbsp;to start again. Do each question repeatedly to ensure you have mastered it.</p>", "extensions": [], "tags": [], "rulesets": {}, "parts": [{"scripts": {}, "prompt": "<p>Suppose you want to set up a scholarship or a donation that&nbsp;gives a regular amount&nbsp;at the end of every {period[2]} forever. If you have $\\$\\var{P}$ to invest at $\\var{ipa}\\%$ p.a. compounded&nbsp;{period[0]}, what amount would be given each {period[2]}?</p>\n<p></p>\n<p>$\\$$&nbsp;[[0]] (to the nearest cent)</p>", "gaps": [{"scripts": {}, "useCustomName": false, "mustBeReducedPC": 0, "customMarkingAlgorithm": "", "unitTests": [], "precisionMessage": "You have not given your answer to the nearest cent.", "precision": "2", "correctAnswerStyle": "plain", "customName": "", "minValue": "C", "showCorrectAnswer": true, "precisionType": "dp", "variableReplacements": [], "extendBaseMarkingAlgorithm": true, "showPrecisionHint": false, "showFeedbackIcon": true, "mustBeReduced": false, "strictPrecision": true, "notationStyles": ["plain", "en", "si-en"], "marks": 1, "precisionPartialCredit": 0, "type": "numberentry", "correctAnswerFraction": false, "maxValue": "C", "variableReplacementStrategy": "originalfirst", "allowFractions": false}], "unitTests": [], "variableReplacements": [], "extendBaseMarkingAlgorithm": true, "customMarkingAlgorithm": "", "showFeedbackIcon": true, "type": "gapfill", "marks": 0, "useCustomName": false, "showCorrectAnswer": true, "customName": "", "sortAnswers": false, "variableReplacementStrategy": "originalfirst"}], "variables": {"period": {"group": "Ungrouped variables", "definition": "random([random('yearly','annually'),1,'year'],[random('half-yearly','semiannually'),2,'half-year'],['quarterly', 4, 'quarter'],['monthly',12,'month'],['daily', 365,'day'])", "name": "period", "description": "", "templateType": "anything"}, "ipa": {"group": "Ungrouped variables", "definition": "ipadec*100", "name": "ipa", "description": "", "templateType": "anything"}, "ipadec": {"group": "Ungrouped variables", "definition": "random(0.02..0.10#0.001)", "name": "ipadec", "description": "", "templateType": "anything"}, "C": {"group": "Ungrouped variables", "definition": "ipadec*P/period[1]", "name": "C", "description": "", "templateType": "anything"}, "Crounded": {"group": "Ungrouped variables", "definition": "precround(C,2)", "name": "Crounded", "description": "", "templateType": "anything"}, "P": {"group": "Ungrouped variables", "definition": "random(5000..100000#1000)", "name": "P", "description": "", "templateType": "anything"}}, "preamble": {"js": "", "css": ""}, "name": "cash flow amount  - ordinary perpetuity", "ungrouped_variables": ["period", "ipadec", "ipa", "P", "C", "Crounded"], "metadata": {"description": "Financial maths. Cash flow amount of an ordinary perpetuity.", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "variablesTest": {"condition": "", "maxRuns": 100}, "advice": "<p>You are asked to find the cash flow amount&nbsp;of an ordinary perpetuity&nbsp;(since the payments are at the end of each&nbsp;period and last forever). Therefore we will use the ordinary perpetuity&nbsp;formula</p>\n<p>$\\displaystyle P=\\frac{C}{i}$</p>\n<p>where $P$ is the present value, $C$ is the cash flow per period&nbsp;and&nbsp;$i$ is the interest rate per period.</p>\n<p>In our&nbsp;situation we have,</p>\n<p>$P=\\var{P}$,</p>\n<p><span data-jme-visible=\"period[1]&gt;1\">$i=\\frac{\\var{ipa}\\%}{\\var{period[1]}}=\\frac{\\var{ipadec}}{\\var{period[1]}}$,</span> <span data-jme-visible=\"period[1]=1\">$i=\\var{ipa}\\%=\\var{ipadec}$,</span></p>\n<p>and therefore we have</p>\n<p>$\\displaystyle \\var{P}=\\frac{C}{\\left(\\simplify[unitDenominator]{{ipadec}/{period[1]}}\\right)}$</p>\n<p>which we need to rearrange to solve for $C$.</p>\n<p>We multiply both sides by $\\left(\\simplify[unitDenominator]{{ipadec}/{period[1]}}\\right)$ (to remove the division by it)</p>\n<p>$\\displaystyle \\var{P}\\left(\\simplify[unitDenominator]{{ipadec}/{period[1]}}\\right)=C$</p>\n<p></p>\n<p>Calculating this we find&nbsp;</p>\n<p>$C=\\$\\var{Crounded}\\quad \\text{(to the nearest cent)}$</p>", "type": "question", "contributors": [{"name": "Ben Brawn", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/605/"}]}]}], "contributors": [{"name": "Ben Brawn", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/605/"}]}