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Rate of change problem involving velocity & acceleration

"}, "advice": "

\\(h=\\var{a}t-4.9t^2\\)

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Recall that speed is the rate of change of position with respect to time   i.e. \\(v=\\frac{dh}{dt}\\)

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\\(v=\\frac{dh}{dt}=\\var{a}-2*4.9t\\)

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when \\(t=\\var{b}\\)

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\\(v=\\var{a}-2*4.9*\\var{b}\\)

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\\(v=\\simplify{{a}-9.8*{b}}m/s\\)

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The missile will reach its maximum height when its speed = 0.   i.e. \\(v=\\frac{dh}{dt}=\\var{a}-2*4.9t=0\\)

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\\(\\var{a}=9.8t\\)

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\\(t=\\var{a}/9.8\\)

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The maximum height reached will occur when \\(t=\\simplify{{a}/9.8}\\)

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\\(h=\\var{a}*\\left(\\simplify{{a}/9.8}\\right)-4.9*\\left(\\simplify{{a}/9.8}\\right)^2\\)

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\\(h=\\simplify{{a}^2/19.6}\\)

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\\(h=\\simplify{{{a}/{19.6}^0.5}^2}\\)

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\n

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A missile is launched straight up in the air. The height of the missile, \\(h\\) metres, above the ground \\(t\\) seconds after the launch button is pressed is given by:

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\\(h=\\var{a}t-4.9t^2\\)

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Calculate the speed of the missile (m/s) \\(\\var{b}\\) seconds after launch. Give your answer correct to one decimal place.

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\\(v = \\) [[0]]m/s

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What is the maximum height achieved by this missile? Give your answer correct to one decimal place.

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\\(h = \\) [[1]]m

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