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Dada la ecuación de la circunferencia $\\simplify{(x-{a})^2+(y-{b})^2={rs}}$.

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Completa los espacios:

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La ecuación $\\simplify{(x-{a})^2+(y-{b})^2={rs}}$ es la ecuación de la circunferencia con radio [[0]]  y centro el punto $\\large($ [[1]], [[2]]$\\large)$. 

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La información anterior nos permite encontrar fácilmente cuatro puntos de la circunferencia:

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Reconociendo que $ (x-a)^2 + (y-b)^2 = r^2 $ es un círculo de radio $r$ con el centro $(a, b) $

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La ecuación de la circunferencia con el radio $ r $ y el centro $ (a, b) $ es $ (x-a) ^ 2 + (y-b) ^ 2 = r ^ 2 $.

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