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Recognising that $(x-a)^2+(y-b)^2=r^2$ is a circle of radius $r$ with centre $(a,b)$ 

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The equation $\\simplify{(x-{a})^2+(y-{b})^2={rs}}$ is the equation of a circle with radius [[0]]  centred at the point $\\large($ [[1]], [[2]]$\\large)$. 

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The above information allows us to find four points of the circle easily:

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The equation of a circle with radius $r$ and centre $(a,b)$ is $(x-a)^2+(y-b)^2=r^2$.

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