// Numbas version: exam_results_page_options {"name": "Angle between vectors", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"metadata": {"notes": "

15/7/2015

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Added tags

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16/07/2012:

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Added tags.

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Question appears to be working correctly.

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Moved the \\rightarrow to the correct place in the solution.

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", "licence": "Creative Commons Attribution 4.0 International", "description": "

Given vectors  $\\boldsymbol{v,\\;w}$, find the angle between them.

"}, "type": "question", "preamble": {"css": "", "js": ""}, "advice": "

Use the formula, $\\boldsymbol{v \\cdot w} = \\lVert \\boldsymbol{v} \\rVert \\lVert \\boldsymbol{w} \\rVert \\cos(\\theta)$m where $\\theta$ is the angle between the vectors.

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Here

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\\begin{align}
\\lVert \\boldsymbol{v} \\rVert &= \\simplify[]{sqrt({s1}^2 + {s2}^2)} \\\\
&= \\sqrt{2}, \\\\[1em]
\\lVert \\boldsymbol{w} \\rVert &= \\simplify[]{sqrt({s3}^2 + {s4}^2)} \\\\
&= \\sqrt{2}, \\\\[1em]
\\boldsymbol{v \\cdot w} &= \\var{v} \\boldsymbol{\\cdot} \\var{w} \\\\
&= \\var{dot(v,w)}
\\end{align}

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So

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\\begin{align}
\\cos(\\theta) &= \\frac{\\var{dot(v,w)}}{\\sqrt{2}\\sqrt{2}} = \\simplify[std]{{dot(v,w)}/2} \\\\
\\implies \\theta &= \\arccos\\left(\\simplify[std]{{dot(v,w)}/{2}}\\right) \\\\
&= \\var{precround(angle,precision)} \\text{ radians}
\\end{align}

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You are given the vectors $\\boldsymbol{v} = \\var{v}$, $\\boldsymbol{w} = \\var{w}$ in $\\mathbb{R}^3$.

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Find the angle between $\\boldsymbol{v}$ and $\\boldsymbol{w}$, in radians.

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Note the angle must be in the range $0$ to $\\pi$.

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Give your answer to {precision} decimal places.

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Angle in radians = [[0]]

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