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If the difference between successive pairs of terms is a constant then the series under examination is an arithmetic progression.

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Ths first term is \\(a\\) and the common difference is \\(d\\).

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The formula for the nth term of the series is given by:    \\(S_n=\\frac{n}{2}\\left(2a+(n-1)d\\right)\\)

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In this example \\(a=\\var{a}\\),  \\(d = \\var{d}\\)  and  \\(n = \\var{n}\\)

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\\(S_\\var{n}=\\frac{\\var{n}}{2}\\left(2*\\var{a}+(\\var{n}-1)\\var{d}\\right)\\)

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\\(S_\\var{n}=\\simplify{{n}/{2}}\\left(\\simplify{2{a}}+\\simplify{({n}-1)*{d}}\\right)\\)

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\\(S_\\var{n}=\\simplify{{n}/{2}}\\left(\\simplify{2{a}+({n}-1)*{d}}\\right)\\)

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\\(S_\\var{n}=\\simplify{{n}*{a}+{n}*({n}-1)*{d}/2}\\)

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The first three terms of a series are given by:  

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\\(\\var{a} + \\simplify{{a}+{d}} + \\simplify{{a}+2*{d}}\\,+ \\, ...........\\)

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Calculate the sum of the first \\(\\var{n}\\) terms of this series.

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\\(S_\\var{n}=\\) [[0]]

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Find the sum of the first n terms of an arithmetic progression

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