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A system is said to be stable if all the poles of the transfer function lie within the unit circle. Otherwise the system is unstable.

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The poles of a transfer function are found by setting the denominator equal to zero and solving.

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Determine whether the system with the following transfer function is stable or unstable.

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poles of a transfer function

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\\(G(z)=\\frac{\\var{d}}{\\var{a}s^2+\\var{b}s+\\var{c}}\\)

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The poles are given by \\(z=\\)[[0]]\\(\\pm j\\)[[1]]

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The modulus of the poles = [[2]]

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The system is stable

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The system is unstable

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To find the poles of a transfer function you must set the denominator to zero and solve.

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\\(\\var{a}s^2+\\var{b}s+\\var{c}=0\\)

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This is a quadratic equation.

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\\(s=\\frac{-\\var{b}\\pm \\sqrt{\\var{b}^2-4*\\var{a}*\\var{c}}}{2*\\var{a}}\\)

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\\(s=\\frac{-\\var{b}\\pm \\sqrt{\\simplify{{b}^2-4*{a}*{c}}}}{\\simplify{2*{a}}}\\)

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\\(s=\\frac{-\\var{b}}{\\simplify{2*{a}}}\\pm \\frac{j\\sqrt{\\simplify{4*{a}*{c}-{b}^2}}}{\\simplify{2*{a}}}\\)

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\\(s=\\var{x}\\pm j\\var{y}\\)

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The modulus of s is thus

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\\(|s|=\\sqrt{\\var{x}^2+\\var{y}^2}=\\var{mod}\\)

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The system is stable if \\(|s|<1\\) otherwise it is unstable.

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